Mysql 分別按月, 日為組group,進行統計排序order

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在資料庫中我們經常用sql語句對錶進行簡單的統計排序,對於日期欄位,我們可以簡單的對其進行order。對於複雜一點的可以按日期中的年,月,日分別進行group,order。


按年份進行group,統計排序:

SELECT YERA(established_time)  ,COUNT(*) AS num <span style="font-size: 13.75px; font-family: Arial, Helvetica, sans-serif;">FROM `table_record` GROUP BY YEAR (established_time)</span>


按月份進行group,統計排序:

方法一:簡單實用

SELECT YEAR(established_time) AS 'year' , MONTH(established_time) AS 'month' , COUNT(*) AS 'count' FROM `table_record` GROUP BY YEAR (established_time) DESC, MONTH(established_time)

效果:

 year   month   count
------  ------  ------- 
2014       1      8320  
2014       2      5837  
2014       3     25069  
2014       4     29820  
2014       5     25060 
2014       6     17615  
2014       7         1  
2013       1      9114  
2013       2      4258

方法二:利用 MySql內建字串串連函數 CONCAT(str1, str2, ...,str3) 。

SELECT  CONCAT(YEAR(established_time),',',MONTH( established_time)) AS data_time ,COUNT(*) AS num FROM `table_record` #group by data_timeGROUP BY YEAR(established_time) DESC,MONTH( established_time)
效果:

data_time     num   
---------  -------- 
2014,1         8320 
2014,2         5837 
2014,3        25069
2014,4        29910
2014,5        25018
2014,6        17347
2014,7            1   
2013,1         9114
2013,2         4258
2013,3         8047

注意這裡不要用:

SELECT  YEAR(established_time)+MONTH( established_time) as data_time 

這是錯誤的,它會造成2010+1=2011的這樣的錯誤。

此外,若僅僅用下面語句,是統計的是多年來每月的資料。

SELECT  MONTH(established_time) AS 'month' , COUNT(*) AS 'count' FROM `tb_gongshangju_record_beijing` GROUP BY  MONTH(established_time) DESC

效果如下:

 month   count  
------  --------
    12     44952
    11     49720
    10     38587
     9     48967
     8     52874
     7     54082
     6     69532
     5     76999
     4     87289
     3     85249
     2     39997
     1     49017
(NULL)     34456



按日期day進行group,統計排序
 
SELECT YEAR(established_time) AS 'year' , MONTH(established_time) AS 'month' ,DAY(established_time) AS 'day', COUNT(*) AS 'count' FROM `table_record` WHERE table_record.`established_time` >= '2014-01-01'GROUP BY YEAR (established_time) DESC, MONTH(established_time) DESC ,DAY(established_time) DESC


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