$set = array('a','b','c','d');
該如何把數組組合,輸出的結果是
a
b
c
b
ab
ac
ad
bc
bd
回複討論(解決方案)
$set = array('a','b','c','d');$res = $set;for($i=0, $p=1; $iArray
(
[0] => a
[1] => b
[2] => c
[3] => d
[4] => ab
[5] => bc
[6] => cd
)
$set = array('a','b','c','d');$res = $set;for($i=0, $p=1; $iArray
(
[0] => a
[1] => b
[2] => c
[3] => d
[4] => ab
[5] => bc
[6] => cd
)
版主這個輸出的和樓主的不一樣啊,我沒太搞懂樓主到底是要怎麼組合輸出這個數組,我的解決方案如下,這裡不用輸出cd就可以了
array (size=10) 0 => string 'a' (length=1) 1 => string 'b' (length=1) 2 => string 'c' (length=1) 3 => string 'd' (length=1) 4 => string 'ab' (length=2) 5 => string 'ac' (length=2) 6 => string 'ad' (length=2) 7 => string 'bc' (length=2) 8 => string 'bd' (length=2) 9 => string 'cd' (length=2)
$set = array('a','b','c','d');$arr=array();for($j=0;$j$v){ for($i=$k;$i<=(3-$v);$i++){ if($v==$set[$i]) continue; $arr[]=$v.$set[$i]; }}print_r($arr);
Array( [0] => a [1] => b [2] => c [3] => d [4] => ab [5] => ac [6] => ad [7] => bc [8] => bd [9] => cd)