有一個數組=>
$arr = array( '0' => 'a value', '1' => 'a value', '2' => 'a value', '4' => 'a value', '5' => 'a value', '7' => 'a value', '10' => 'a value', '11' => 'a value', '12' => 'a value', );
同時,我有一個
$num
假定
$num=15
此時,我想得到這個數組=>
$arr = array( '0' => 'a value', '1' => 'a value', '2' => 'a value', '3' => 'kong', '4' => 'a value', '5' => 'a value', '6' => 'kong', '7' => 'a value', '8' => 'kong', '9' => 'kong', '10' => 'a value', '11' => 'a value', '12' => 'a value', '13' => 'kong', '14' => 'kong', '15' => 'kong', );
請問有什麼便捷、快速的方法,產生這個數組
回複討論(解決方案)
$arr = array('0' => 'a value','1' => 'a value','2' => 'a value','4' => 'a value','5' => 'a value','7' => 'a value','10' => 'a value','11' => 'a value','12' => 'a value',);$num=15;$tmp = range(0,$num);$keys = array_keys($arr);$kongArr = array_fill_keys(array_diff($tmp,$keys),'kong');//因為是數字索引,若使用 array_merge 會重新索引,不能排序foreach($kongArr as $k=>$v){$arr[$k] = $v;}ksort($arr);echo "";print_r($arr);echo "
";/*Array( [0] => a value [1] => a value [2] => a value [3] => kong [4] => a value [5] => a value [6] => kong [7] => a value [8] => kong [9] => kong [10] => a value [11] => a value [12] => a value [13] => kong [14] => kong [15] => kong)*/
沒那麼複雜
$arr = array( '0' => 'a value', '1' => 'a value', '2' => 'a value', '4' => 'a value', '5' => 'a value', '7' => 'a value', '10' => 'a value', '11' => 'a value', '12' => 'a value',);$num = 15;$b = $arr + array_fill(0, $num+1, 'kong');ksort($b);print_r($b);
Array( [0] => a value [1] => a value [2] => a value [3] => kong [4] => a value [5] => a value [6] => kong [7] => a value [8] => kong [9] => kong [10] => a value [11] => a value [12] => a value [13] => kong [14] => kong [15] => kong)