PHP獲得跳轉的真真實位址執行個體_PHP教程

現在有很多的短網址應用，點擊就跳轉到縮短之前的網址了，那今天我們就來看一下，PHP如何擷取短網址跳轉之前的網址，其實也很簡單，就是用php的get_headers 函數，

取得Response Headers，之後慢慢分析就行了。

給出具體實現方法：

代碼如下	複製代碼
$header = get_headers($url, 1); if (strpos($header[0], ’301′) || strpos($header[0], ’302′)) { if (is_array($header['Location'])) { return $header['Location'][count($header['Location'])-1]; } else { return $header['Location']; } } else { return $url; }

執行個體二

代碼如下

複製代碼

// echo get_redirect_url('http://www.111cN.nEt'); //輸出結果為：http://code.google.com/android/ function get_redirect_url($url){ $redirect_url = null; $url_parts = @parse_url($url); if (!$url_parts) return false; if (!isset($url_parts['host'])) return false; //can't process relative URLs if (!isset($url_parts['path'])) $url_parts['path'] = '/'; $sock = fsockopen($url_parts['host'], (isset($url_parts['port']) ? (int)$url_parts['port'] : 80), $errno, $errstr, 30); if (!$sock) return false; $request = "HEAD " . $url_parts['path'] . (isset($url_parts['query']) ? '?'.$url_parts['query'] : '') . " HTTP/1.1rn"; $request .= 'Host: ' . $url_parts['host'] . "rn"; $request .= "Connection: Closernrn"; fwrite($sock, $request); $response = ''; while(!feof($sock)) $response .= fread($sock, 8192); fclose($sock); if (preg_match('/^Location: (.+?)$/m', $response, $matches)){ if ( substr($matches[1], 0, 1) == "/" ) return $url_parts['scheme'] . "://" . $url_parts['host'] . trim($matches[1]); else return trim($matches[1]); } else { return false; } }

http://www.bkjia.com/PHPjc/631515.htmlwww.bkjia.comtruehttp://www.bkjia.com/PHPjc/631515.htmlTechArticle現在有很多的短網址應用，點擊就跳轉到縮短之前的網址了，那今天我們就來看一下，PHP如何擷取短網址跳轉之前的網址，其實也很簡單，...

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