php json轉數組出錯求助
1:先輸出json
//組合醫生資訊JSON
$jsonDoctorInfo = "{\"mecdoctor\":[";
$jsonDoctorInfo .= "{\"doctorId\":\"".$doctorId."\",\"doctorName\":\"".$strDoctorName."\", \"doctorprice\":\"".$strPrice."\",\"expertise\":\"".$strExpertise."\",\"departments\":\"".$strdepartments."\",\"doctorTitle\":\"".$strTitle."\",\"doctorPhoto\":\"".$strDoctorPhoto."\"}";
$jsonDoctorInfo .= "]}";
2:擷取並decode
$jsonGetDoctorInfoData = json_encode($jsonGetDoctorInfoData);
$objGetDoctorInfoData = json_decode($jsonGetDoctorInfoData);
輸出:
{"mecdoctor":[{"doctorId":"","doctorName":"XXXX", "doctorprice":"122","expertise":"XXXXX","departments":"醫內科","doctorTitle":"主任醫師","doctorPhoto":"hmh"}]}
3:將json轉換成數組
//解析JSON資料
function _json_decode($json){
$comment = false;
$out = '$x=';
for ($i=0; $iif (!$comment){
if ( ($json[$i] == '{') || ($json[$i] == '[') )
$out .= ' array(';
else if (($json[$i] == '}') || ($json[$i] == ']'))
$out .= ')';
else if ($json[$i] == ':')
$out .= '=>';
else
$out .= $json[$i];
}else
$out .= $json[$i];
if($json[$i]== '"' && $json[($i-1)]!="\\")
$comment = !$comment;
}
eval($out.";");
return $x;
}
4:出現問題
Parse error: syntax error, unexpected T_DOUBLE_ARROW in /home/u945504094/public_html/config/config.inc.php(876) : eval()'d code on line 1
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------解決方案--------------------
沒有問題呀
$s = '{"mecdoctor":[{"doctorId":"","doctorName":"XXXX", "doctorprice":"122","expertise":"XXXXX","departments":"醫內科","doctorTitle":"主任醫師","doctorPhoto":"hmh"}]}';
print_r(_json_decode($s));
function _json_decode($json){
$comment = false;
$out = '$x=';
for ($i=0; $i if (!$comment){
if ( ($json[$i] == '{')
------解決方案--------------------
($json[$i] == '[') )
$out .= ' array(';
else if (($json[$i] == '}')
------解決方案--------------------
($json[$i] == ']'))
$out .= ')';
else if ($json[$i] == ':')
$out .= '=>';
else
$out .= $json[$i];
}else
$out .= $json[$i];
if($json[$i]== '"' && $json[($i-1)]!="\\")
$comment = !$comment;
}
eval($out.";");
return $x;
}
Array
(
[mecdoctor] => Array
(
[0] => Array
(
[doctorId] =>