php的mssql資料庫連接類執行個體_PHP

本文執行個體講述了php的mssql資料庫連接類執行個體代碼,分享給大家供大家參考。

具體實現代碼如下:

代碼如下:

class DB_Sql {
var $Host = "";
var $Database = "";
var $User = "";
var $Password = "";
var $Link_ID = 0;
var $Query_ID = 0;
var $Record = array();
var $Row = 0;

var $Errno = 0;
var $Error = "";
var $Auto_Free = 0; ## set this to 1 to automatically free results

function DB_Sql($query = "") {
$this->query($query);
}
function connect() {
if ( 0 == $this->Link_ID ) {
$this->Link_ID=mssql_connect($this->Host, $this->User, $this->Password);
if (!$this->Link_ID)
$this->halt("Link-ID == false, mssql_pconnect failed");
else
@mssql_select_db($this->Database, $this->Link_ID);
}
}
function free_result(){
mssql_free_result($this->Query_ID);
$this->Query_ID = 0;
}

function query($Query_String)
{

/* No empty queries, please, since PHP4 chokes on them. */
if ($Query_String == "")
/* The empty query string is passed on from the constructor,
* when calling the class without a query, e.g. in situations
* like these: '$db = new DB_Sql_Subclass;'
*/
return 0;
if (!$this->Link_ID)
$this->connect();

# printf("
Debug: query = %s
", $Query_String);

$this->Query_ID = mssql_query($Query_String, $this->Link_ID);
$this->Row = 0;
if (!$this->Query_ID) {
$this->Errno = 1;
$this->Error = "General Error (The MSSQL interface cannot return detailed error messages).";
$this->halt("Invalid SQL: ".$Query_String);
}
return $this->Query_ID;
}

function next_record() {

if ($this->Record = mssql_fetch_row($this->Query_ID)) {
// add to Record[]
$count = mssql_num_fields($this->Query_ID);
for ($i=0; $i<$count; $i++){
$fieldinfo = mssql_fetch_field($this->Query_ID,$i);
$this->Record[strtolower($fieldinfo->name)] = $this->Record[$i];
}
$this->Row += 1;
$stat = 1;
} else {
if ($this->Auto_Free) {
$this->free_result();
}
$stat = 0;
}
return $stat;
}

function seek($pos) {
mssql_data_seek($this->Query_ID,$pos);
$this->Row = $pos;
}
function metadata($table) {
$count = 0;
$id = 0;
$res = array();
$this->connect();
$id = mssql_query("select * from $table", $this->Link_ID);
if (!$id) {
$this->Errno = 1;
$this->Error = "General Error (The MSSQL interface cannot return detailed error messages).";
$this->halt("Metadata query failed.");
}
$count = mssql_num_fields($id);

for ($i=0; $i<$count; $i++) {
$info = mssql_fetch_field($id, $i);
$res[$i]["table"] = $table;
$res[$i]["name"] = $info["name"];
$res[$i]["len"] = $info["max_length"];
$res[$i]["flags"] = $info["numeric"];
}
$this->free_result();
return $res;
}

function affected_rows() {
// Not a supported function in PHP3/4. Chris Johnson, 16May2001.
// return mssql_affected_rows($this->Query_ID);
$rsRows = mssql_query("Select @@rowcount as rows", $this->Link_ID);
if ($rsRows) {
return mssql_result($rsRows, 0, "rows");
}
}

function num_rows() {
return mssql_num_rows($this->Query_ID);
}

function num_fields() {
return mssql_num_fields($this->Query_ID);
}
function nf() {
return $this->num_rows();
}

function np() {
print $this->num_rows();
}

function f($Field_Name) {
return $this->Record[strtolower($Field_Name)];
}

function p($Field_Name) {
print $this->f($Field_Name);
}

function halt($msg) {
printf("Database error: %s
", $msg);
printf("MSSQL Error: %s (%s)
",
$this->Errno,
$this->Error);
die("Session halted.");
}
}

希望本文所述對大家的PHP程式設計有所協助。

