就是一道簡單的日期計算題
但是還是有很多要注意的問題,一不小心就會錯,不過這種題目拿邊緣資料測試就可以看出是哪裡錯了,比如30,365,36之類的..
#include <cstdio>using namespace std;int rm[]={31,29,31,30,31,30,31,31,30,31,30,31};int pm[]={31,28,31,30,31,30,31,31,30,31,30,31};int isr(int x){//判斷閏年 if(x%400==0||x%100!=0&&x%4==0)return 1;return 0;}int main(){int n;while(scanf("%d",&n)){int y=2000,m=0,d=0,dd;if(n==-1)break;dd=n;while(n>=(isr(y)?366:365)){//減去年份,注意是>= n-=(isr(y)?366:365);y++;}while(n>=(isr(y)?rm[m]:pm[m])){//減去月份 n-=(isr(y)?rm[m]:pm[m]);m=(m+1)%12;}d=n%(isr(y)?rm[m]:pm[m])+1;//算日期 printf("%d",y);m=m+1;m<10?printf("-0%d",m):printf("-%d",m);d<10?printf("-0%d ",d):printf("-%d ",d);switch(dd%7){case 1:printf("Sunday");break;case 2:printf("Monday");break;case 3:printf("Tuesday");break;case 4:printf("Wednesday");break;case 5:printf("Thursday");break;case 6:printf("Friday");break;case 0:printf("Saturday");break;}printf("\n");}return 0;}