有關UNION與WHERE的有關問題

來源:互聯網
上載者:User
有關UNION與WHERE的問題
$id=$_GET['id']; //另一頁面超連結傳來的值
$id = "where WebMailUserN=".$id;
//--遍曆數組中的所有表中的資料,並顯示欄位內容
$table = array("content_201202","content_201203","content_201204");
$select = array();
foreach($table as $v) {
$select[]= "(select * from $v $id)";
}
echo $sqll = join('UNION ',$select);
$sqll = mysql_query($sqll);
$num = mysql_num_rows($sqll);//記錄總條數,為了分頁

$sqln = join(' UNION ',$select)." limit $page $pagesize";
$sqln = mysql_query($sqln);
while($row = mysql_fetch_array($sqln)){.......}

(select * from content_201208 where WebMailUserN=$id)UNION (select * from content_201209 where WebMailUserN=$id)UNION (select * from content_201210 where WebMailUserN=$id)
Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in F:\www_local\G04\list_content.php on line 49

Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in F:\www_local\G04\list_content.php on line 53


上面代碼不知道那有錯,不顯示資料

------解決方案--------------------
你需要將id連在url上傳至下一頁
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