在php中遞迴查詢節點,該如何處理

在php中遞迴查詢節點
部門樹下，我已經查詢出所有的部門樹節點id，我想根據前台傳過來的根節點id，在php後台中遞迴出所有前台傳過來的根節點的子節點，我想問問這種方式可行不，如果可行，應該怎麼實現？

------解決方案--------------------

1.樣本1
function find_child($ar, $id='id', $pid='pid') {
  foreach($ar as $v) $t[$v[$id]] = $v;
  foreach ($t as $k => $item){
    if( $item[$pid] ) {
    $t[$item[$pid]]['child'][] =&$t[$k];
      unset($t[$k]);
    }
  }
  return $t;
}
$data = array(
array('ID'=>1,'PARENT'=>0,'NAME'=>'kobe'),
array('ID'=>2,'PARENT'=>0,'NAME'=>'jama'),
array('ID'=>3,'PARENT'=>1,'NAME'=>'kobe1'),
array('ID'=>4,'PARENT'=>2,'NAME'=>'jama1'),
array('ID'=>5,'PARENT'=>0,'NAME'=>'lizhi'),
array('ID'=>6,'PARENT'=>1,'NAME'=>'kobe2'),
);

$c = find_child($data, 'ID', 'PARENT');
echo '
';
print_r($c);
?>


2.樣本2

function find_child($ar, $id='id', $pid='pid') {
  foreach($ar as $v) $t[$v[$id]] = $v;
  foreach ($t as $k => $item){
    if( $item[$pid] ) {
    $t[$item[$pid]]['child'][] =&$t[$k];
      unset($t[$k]);
    }
  }
  return $t;
}
$data = array(
array('ID'=>1,'PARENT'=>0,'NAME'=>'kobe'),
array('ID'=>2,'PARENT'=>0,'NAME'=>'jama'),
array('ID'=>3,'PARENT'=>1,'NAME'=>'kobe1'),
array('ID'=>4,'PARENT'=>2,'NAME'=>'jama1'),
array('ID'=>5,'PARENT'=>0,'NAME'=>'lizhi'),
array('ID'=>6,'PARENT'=>1,'NAME'=>'kobe2'),
);

$c = find_child($data, 'ID', 'PARENT');
echo '
';
print_r($c);
?>

------解決方案--------------------

$arr = array(
1=>array('id'=>'1','name'=>'1','pid'=>'0'),
2=>array('id'=>'2','name'=>'2','pid'=>'0'),
3=>array('id'=>'3','name'=>'11','pid'=>'1'),
4=>array('id'=>'4','name'=>'22','pid'=>'2'),
);
function tree($arr){
$t = array();
foreach($arr as $v){
if (isset($arr[$v['pid']])){
$arr[$v['pid']]['child'][] = &$arr[$v['id']];
}else{
$t[] = &$arr[$v['id']];
}
}
return $t;
}
echo '
';print_r(tree($arr));
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