Access資料庫中Round用法

Access資料庫中Round用法

四捨五入的問題

select round(83.124,2) as t from jqdltb

顯示為:83.12

select round(83.125,2) as t from jqdltb

顯示為:83.12

select round(83.126,2) as t from jqdltb

顯示為:83.13

問題來了，就是四捨五入怎麼變成五舍六入了呢？

下面是用這個方法來調整達到四捨五入的方法:

使用int函數和加0.005,然後*100，再然後/100

如下所示:

select int((83.121+0.005)*100)/100 as t from jqdltb

顯示為:83.12

select int((83.124+0.005)*100)/100 as t from jqdltb

顯示為:83.12

select int((83.125+0.005)*100)/100 as t from jqdltb

顯示為:83.13

select int((83.126+0.005)*100)/100 as t from jqdltb

顯示為:83.13

select int((83.129+0.005)*100)/100 as t from jqdltb

顯示為:83.13

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