sdut1916 字串擴充

來源:互聯網
上載者:User
#include<iostream>#include<cstdio>#include<cstring>using namespace std;char a[1005];int main(){int t;int len;int i,j;scanf("%d",&t);getchar();while(t--){gets(a);len=strlen(a);printf("%c",a[0]);for(i=1;i<len;i++){if(a[i]=='-'&&a[i-1]<=a[i+1]&&((a[i-1]>='a'&&a[i-1]<='z'&&a[i+1]>='a'&&a[i+1]<='z')||(a[i-1]>='A'&&a[i-1]<='Z'&&a[i+1]>='A'&&a[i+1]<='Z')||(a[i-1]>='0'&&a[i-1]<='9'&&a[i+1]>='0'&&a[i+1]<='9'))){for(j=a[i-1]+1;j<=a[i+1]-1;j++)printf("%c",j);}elseprintf("%c",a[i]);}printf("\n");}return 0;} /**************************************Problem id: SDUT OJ 1916 Result: Accepted Take Memory: 452K Take Time: 0MS Submit Time: 2013-05-26 17:44:53  **************************************/

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