Shell指令碼實現的猜數字小遊戲_linux shell

產生的密碼和使用者輸入可以接受重複數字。
所以相對一般規則的猜數字可能難度要大不少。

本版本規則：

A--數字對，位置也對
B--排除A的結果後，數字對，但位置不對

開始後，系統化初始化一個4位可重複數字，如“1223”。假設使用者第一次輸入“1234”，那麼系統將提示“2A1B”，前兩位元字“12”相同並且位置也相同，為“2A”。後兩位元字中，使用者輸入的“3”與密文中“3”相同，但兩者位置不同，則為“1B”，最終結果為“2A1B”。

再假設使用者此時輸入“1232”，那麼結果則為“2A2B”，計算方法與前次一樣。

代碼如下：

#!/bin/bashclearechoecho "###################################################################"echo "# this is a bash-shell game write by Email:breeze7086@gmail.com #"echo "# the game called *digits*,and this version have repeated numbers #"echo "#              version 1.0              #"echo "###################################################################"echo -e "\n\n"declare INPUTdeclare PASSWORDdeclare Adeclare Bdeclare Xdeclare Ydeclare LOOP#This funtion init the variable PASSWORD that user need to guessinit_password(){    PASSWORD=`echo $(($RANDOM%10000))`    echo $PASSWORD | grep '^[0-9]\{4\}$' >/dev/null 2>&1    if [ $? != 0 ]    then        init_password    else        input    fi}#This funtion accept the input from user's keyboardinput(){    echo -n "please input a number between 0000-9999:"    read INPUT    echo $INPUT | grep '^[0-9]\{4\}$' >/dev/null 2>&1    if [ $? != 0 ]    then        echo "retry a number between 0000-9999 and do not input a char"        input    else        judge    fi}#This funtion is the main funtionjudge(){    X=$INPUT    Y=$PASSWORD    while [ $INPUT != $PASSWORD ]    do        A=0        B=0        judge_a        judge_b        LOOP=`expr $LOOP + 1`        echo "****************************"        echo "*      "$A"A"$B"B      *"        echo "****************************"        input    done}#This funtion count the variable A's valuejudge_a(){        for i in `seq 4`        do            VAR_INPUT=`expr substr "$X" $i 1`            for j in `seq 4`            do                VAR_PASSWORD=`expr substr "$Y" $j 1`                if [[ $VAR_INPUT = $VAR_PASSWORD && $VAR_INPUT != "" && $VAR_PASSWORD != "" && $i = $j ]]                then                    A=`expr $A + 1`                    X=`expr substr $X 1 "$[$i-1]"``expr substr $X "$[$i+1]" 4`                    Y=`expr substr $Y 1 "$[$i-1]"``expr substr $Y "$[$i+1]" 4`                    judge_a                fi            done        done}#This funtion count the variable B's valuejudge_b(){        for i in `seq 4`        do            VAR_INPUT=`expr substr "$X" $i 1`            for j in `seq 4`            do                VAR_PASSWORD=`expr substr "$Y" $j 1`                if [[ $VAR_INPUT = $VAR_PASSWORD && $VAR_INPUT != "" && $VAR_PASSWORD != "" ]]                then                    B=`expr $B + 1`                    X=`expr substr "$X" 1 "$[$i-1]"``expr substr "$X" "$[$i+1]" 4`                    Y=`expr substr "$Y" 1 "$[$j-1]"``expr substr "$Y" "$[$j+1]" 4`                    judge_b                fi            done        done}#This is the begin of scriptLOOP=1init_passwordecho "#############################################"echo "#congratulations!You have tried $LOOP times!  #"echo "#    The password is $PASSWORD !       #"echo "#############################################"