簡單但易錯的onclick-報錯__javascript

來源:互聯網
上載者:User
Uncaught TypeError: Cannot set property 'onclick' of null;

一句話“確保click事件的dom節點渲染先於JS執行。”解決。

自己寫的一段原生JS的click事件,JS代碼是寫在首頁

<script type="text/javascript">        var all_features = document.getElementById("all_features");        var all_features_down = document.getElementById("all_features_down");        all_features.onclick=function () {            var price_content = document.getElementsByClassName("price_content");            for (var i = 0; i < price_content.length; i++) {                price_content[i].style.display = "none";            }            all_features.style.display = "none";            all_features_down.style.display = "block";        };        all_features_down.onclick=function () {            var price_content_down = document.getElementsByClassName("price_content");            for (var i = 0; i < price_content_down.length; i++) {                price_content_down[i].style.display = "block";            }            all_features.style.display = "block";            all_features_down.style.display = "none";        };    </script>

代碼沒什麼看的,關鍵的是我點擊的dom沒有在首頁,還木有渲染出來,所以報了以上錯誤(雖說是錯誤,但對使用者是無感的,沒有任何影響,使用者點擊到了那個頁面,照樣是可以正常操作的)。

不過程式員的潔癖(no error):
改成 了

function trigger_switch_up() {            var price_content = document.getElementsByClassName("price_content");            for (var i = 0; i < price_content.length; i++) {                price_content[i].style.display = "none";            }            all_features.style.display = "none";            all_features_down.style.display = "block";        };        function () trigger_switch_down{            var price_content_down = document.getElementsByClassName("price_content");            for (var i = 0; i < price_content_down.length; i++) {                price_content_down[i].style.display = "block";            }            all_features.style.display = "block";            all_features_down.style.display = "none";        };
<div onClick="trigger_switch_down()">Some Content</div>

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