snoopy類比登入有關問題

snoopy類比登入問題

PHP code

    New Document      fetchform("http://www.phpx.com/happy/logging.php?action=login");echo $snoopy->results."
"; */$submit_url = "http://www.phpx.com/happy/logging.php?action=login"; $submit_vars["cookietime"] = "2592000";$submit_vars["loginfield"] = "username";$submit_vars["username"] = "你的使用者名稱"; //你的使用者名稱$submit_vars["password"] = "你的密碼";  //你的密碼$submit_vars["questionid"] = "0";$submit_vars["answer"] = "";    $submit_vars["loginsubmit"] = "登入";//$submit_vars["loginsubmit"] = "dl"; //可以//$submit_vars["loginsubmit"] = ""; //不行//問題1：為什麼要加入上面那句：$submit_vars["loginsubmit"] = "登入"，而且“登入”改為任何字眼都可以，但“”不可以$snoopy->submit($submit_url,$submit_vars);echo $snoopy->results;//問題2：登入成功後跳轉到http://127.0.0.1/snoopy/index.php?> 

------解決方案--------------------
1.這個欄位是表單的一個隱藏欄位,如:.
2.這是由表單提交後的處理指令碼決定,照你說的情況,後面判斷是用的!empty($_POST[loginsubmit]),不是Snoopy的問題.
3.$snoopy->submit($submit_url,$submit_vars);
$snoopy->fetch('http://www.phpx.com/happy/index.php');//直接抓取最終頁面
echo $snoopy->results;

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