strtok處理字串常量

strtok()函數不能直接處理const char*, 用strncpy得到一個char型數組， 對這個temp數組進行處理即可。

#include <stdio.h>#include <stdlib.h>#include <string.h>  int main (void){    char *string = "T01:91+:123";    char tmp[16];    char* s;     /* Strtok can not do with const char*, so I use strncpy copy it to an char array */    strncpy(tmp, string, sizeof(string));     s = strtok (tmp, "T");    printf("string: %s\n", string); // 01:91+:123    s = strtok (s, ":");     printf("city id: %s\n", s); // 01    return 0;}

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gist: https://gist.github.com/wusuopubupt/64cd0cb29bf67ed82af4

Update:

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#include<string.h>#include<stdio.h>int main(void){    char input[16]="abc,d";    char *p;    p=strtok(input,",");    if(p) printf("%s\n",p);    p=strtok(NULL,","); //注意這裡。    if(p) printf("%s\n",p);    return 0;}

輸出：

abc

d