問題有點繞，頭暈者勿進^_^

array ( 0 => array ( 'id' => '10', 'title' => 'a','type' => '1', 'bian'=>'1'),
1 => array ( 'id' => '10', 'title' => 'a','type' => '1', 'bian'=>2),
2 => array ( 'id' => '11', 'title' => 'b','type' => '2', 'bian'=>'1'),
3 => array ( 'id' => '11', 'title' => 'c','type' => '2', 'bian'=>'2'),
)
當type=1去除相同id重複並且key變成ID，當type=2時KEY變成id_bian的形式,最終轉成以下數組
array ( 0 => array ( '10' => '', '11_1' => '','11_2' => ''),)
然後在與下面數組合并
array ( 0 => array ( '10' => '1','11_2' => '1'),
1 => array ( '10' => '1','11_2' => '1'),
2 => array ( '11_1' => '1','11_2' => '1'),
3 => array ( '10' => '2','11_2' => '1'),
)
最終得到
array ( 0 => array ( '10' => '1','11_1'=>'','11_2' => '1'),
1 => array ( '10' => '1', '11_1 => '', 11_2' => '1'),
2 => array ( '10' => '', '11_1' => '1', '11_2' => '1'),
3 => array ( '10' => '2', '11_1' => '', '11_2' => '1'),
)

回複討論(解決方案)

$a = array ( 0 => array ( 'id' => '10', 'title' => 'a','type' => '1', 'bian'=>'1'),  1 => array ( 'id' => '10', 'title' => 'a','type' => '1', 'bian'=>'2'),  2 => array ( 'id' => '11', 'title' => 'b','type' => '2', 'bian'=>'1'), 3 => array ( 'id' => '11', 'title' => 'c','type' => '2', 'bian'=>'2'),  );$b = array ( 0 => array ( '10' => '1','11_2' => '1'),  1 => array ( '10' => '1','11_2' => '1'), 2 => array ( '11_1' => '1','11_2' => '1'), 3 => array ( '10' => '2','11_2' => '1'),  );$t = array();foreach($a as $item) {  if($item['type'] == '1') {    $t[$item['id']] = '';  }else $t[$item['id'].'_'.$item['bian']] = '';}$c = array();foreach($b as $v) {  $r = array();  foreach($t as $k=>$n) $r[$k] = @$v[$k];  $c[] = $r;}print_r($c);

Array(    [0] => Array        (            [10] => 1            [11_1] =>             [11_2] => 1        )    [1] => Array        (            [10] => 1            [11_1] =>             [11_2] => 1        )    [2] => Array        (            [10] =>             [11_1] => 1            [11_2] => 1        )    [3] => Array        (            [10] => 2            [11_1] =>             [11_2] => 1        ))

$a = array ( 0 => array ( 'id' => '10', 'title' => 'a','type' => '1', 'bian'=>'1'),  1 => array ( 'id' => '10', 'title' => 'a','type' => '1', 'bian'=>'2'),  2 => array ( 'id' => '11', 'title' => 'b','type' => '2', 'bian'=>'1'), 3 => array ( 'id' => '11', 'title' => 'c','type' => '2', 'bian'=>'2'),  );$b = array ( 0 => array ( '10' => '1','11_2' => '1'),  1 => array ( '10' => '1','11_2' => '1'), 2 => array ( '11_1' => '1','11_2' => '1'), 3 => array ( '10' => '2','11_2' => '1'),  );$t = array();foreach($a as $item) {  if($item['type'] == '1') {    $t[$item['id']] = '';  }else $t[$item['id'].'_'.$item['bian']] = '';}$c = array();foreach($b as $v) {  $r = array();  foreach($t as $k=>$n) $r[$k] = @$v[$k];  $c[] = $r;}print_r($c);

Array(    [0] => Array        (            [10] => 1            [11_1] =>             [11_2] => 1        )    [1] => Array        (            [10] => 1            [11_1] =>             [11_2] => 1        )    [2] => Array        (            [10] =>             [11_1] => 1            [11_2] => 1        )    [3] => Array        (            [10] => 2            [11_1] =>             [11_2] => 1        ))

如果在$C裡追加$t做為元素是不是要重新遍曆？
追加 array ( '10' => '', '11_1' => '','11_2' => '')做為$c的

不太明白你的意思

不太明白你的意思

$a = array ( 0 => array ( 'id' => '10', 'title' => 'a','type' => '1', 'bian'=>'1'),  1 => array ( 'id' => '10', 'title' => 'a','type' => '1', 'bian'=>'2'),  2 => array ( 'id' => '11', 'title' => 'b','type' => '2', 'bian'=>'1'), 3 => array ( 'id' => '11', 'title' => 'c','type' => '2', 'bian'=>'2'),  );$b = array ( 0 => array ( '10' => '1','11_2' => '1'),  1 => array ( '10' => '1','11_2' => '1'), 2 => array ( '11_1' => '1','11_2' => '1'), 3 => array ( '10' => '2','11_2' => '1'),  );$t = array();foreach($a as $item) {  if($item['type'] == '1') {    $t[$item['id']] = '';  }else $t[$item['id'].'_'.$item['bian']] = '';}$c = array();foreach($b as $v) {  $r = array();  foreach($t as $k=>$n) $r[$k] = @$v[$k];  $c[] = $r;}print_r($c);

就是數組a整裡的結果插到$c中，是不是一定要把$c在遍曆一次？

並沒有遍曆 $c 啊

