try catch finally用法

1.catch不到拋出的異常，則結束此函數的執行，拋出異常位置後面的代碼都不執行

public class Test {</p><p>/**<br /> * @param args<br /> */<br />public static void main(String[] args) {<br />// TODO Auto-generated method stub<br />System.out.println("--- main() start --->");</p><p>hello();</p><p>testSeq();</p><p>System.out.println("--- main() end <---");<br />}</p><p>public static void hello() {<br />try {<br />method();<br />} catch (NullPointerException e) {<br />e.printStackTrace();<br />System.out.println("NullPointerException occured.");<br />} finally {<br />System.out.println("finally...");<br />}</p><p>System.out.println("after hello");<br />}</p><p>public static void method() {<br />//throw new NullPointerException();<br />throw new ArithmeticException();<br />}</p><p>public static String testSeq() {<br />String result = "";<br />int i = 0;</p><p>try {<br />i = 7 / i;<br />System.out.println("in try...");<br />} catch (NullPointerException e) {<br />e.printStackTrace();<br />System.out.println("In catch...");<br />} finally {<br />System.out.println("In finally....");<br />}<br />System.out.println("after...");</p><p>return result;<br />}<br />}

 

輸出結果：

--- main() start --->
finally...
Exception in thread "main" java.lang.ArithmeticException
 at com.min.Test.method(Test.java:35)
 at com.min.Test.hello(Test.java:22)
 at com.min.Test.main(Test.java:13)

 

2.catch到拋出的異常，則繼續執行此函數，拋出異常位置後面的代碼也執行

package com.min;</p><p>public class Test {</p><p>/**<br /> * @param args<br /> */<br />public static void main(String[] args) {<br />// TODO Auto-generated method stub<br />System.out.println("--- main() start --->");</p><p>hello();</p><p>testSeq();</p><p>System.out.println("--- main() end <---");<br />}</p><p>public static void hello() {<br />try {<br />method();<br />} catch (NullPointerException e) {<br />e.printStackTrace();<br />System.out.println("NullPointerException occured.");<br />} finally {<br />System.out.println("finally...");<br />}</p><p>System.out.println("after hello");<br />}</p><p>public static void method() {<br />throw new NullPointerException();<br />//throw new ArithmeticException();<br />}</p><p>public static String testSeq() {<br />String result = "";<br />int i = 0;</p><p>try {<br />i = 7 / i;<br />System.out.println("in try...");<br />} catch (NullPointerException e) {<br />e.printStackTrace();<br />System.out.println("In catch...");<br />} finally {<br />System.out.println("In finally....");<br />}<br />System.out.println("after...");</p><p>return result;<br />}<br />}

輸出結果：

--- main() start --->
java.lang.NullPointerException
 at com.min.Test.method(Test.java:34)
 at com.min.Test.hello(Test.java:22)
 at com.min.Test.main(Test.java:13)
NullPointerException occured.
finally...
after hello
In finally....
Exception in thread "main" java.lang.ArithmeticException: / by zero
 at com.min.Test.testSeq(Test.java:43)
 at com.min.Test.main(Test.java:15)