malloc二維數組的2種方法

#include <malloc.h>#include <stdio.h>int main(){    int **a = malloc(sizeof(int)*3);    a[0]= malloc(sizeof(int)*2);    a[1]= malloc(sizeof(int)*2);    a[2]= malloc(sizeof(int)*2);    a[0][0] =1;    a[0][1] =2;    a[1][0] =3;    a[1][1] = 4;    a[2][0] =5;    a[2][1] = 6;    printf("%d\t%d\t%d\t%d\t%d\t%d\n",a[0][0],a[0][1],a[1][0],a[1][1],a[2][0],a[2][1]);     free(a[0]);    free(a[1]);    free(a[2]);    free(a);}

#include <malloc.h>#include <stdio.h>int main(){    int (*a)[2] = malloc(sizeof(int)*3*2);    a[0][0] =1;    a[0][1] =2;    a[1][0] =3;    a[1][1] = 4;    a[2][0] =5;    a[2][1] = 6;    printf("%d\t%d\t%d\t%d\t%d\t%d\n",a[0][0],a[0][1],a[1][0],a[1][1],a[2][0],a[2][1]);     free(a);}