UVA Mapping the Swaps

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題目如下：

Mapping the Swaps

Sorting an array can be done by swapping certain pairs of adjacent entriesin the array. This is the fundamental technique used in the well-knownbubble sort. If we list the identities of the pairs to be swapped, in thesequence they are to be swapped, we obtain what might be called a swap map.For example, suppose we wish to sort the array A whose elements are 3, 2,and 1 in that order. If the subscripts for this array are 1, 2, and 3,sorting the array can be accomplished by swapping A2 and A3, then swapping A1and A2, and finally swapping A2 and A3. If a pair is identified in a swapmap by indicating the subscript of the first element of the pair to beswapped, then this sorting process would be characterized with the swap map2 1 2.

It is instructive to note that there may be many ways in which swapping ofadjacent array entries can be used to sort an array. The previous array,containing 3 2 1, could also be sorted by swapping A1 and A2, then swappingA2 and A3, and finally swapping A1 and A2 again. The swap map that describesthis sorting sequence is 1 2 1.

For a given array, how many different swap maps exist? A little thoughtwill show that there are an infinite number of swap maps, since sequentialswapping of an arbitrary pair of elements will not change the order of the elements. Thus the swap map 1 1 1 2 1 will also leave our arrayelements in ascending order. But how many swap maps of minimum size willplace a given array in order? That is the question you are to answer in this problem.

Input

The input data will contain an arbitrary number of test cases, followed by asingle 0. Each test case will have a integern that gives the size of anarray, and will be followed by the n integer values in the array.

Output

For each test case, print a message similar to those shown in thesample output below. In no test case willn be larger than 5.

Sample Input

2 9 72 12 503 3 2 13 9 1 50

Sample Output

There are 1 swap maps for input data set 1.There are 0 swap maps for input data set 2.There are 2 swap maps for input data set 3.There are 1 swap maps for input data set 4.

求將一個數組排序的不同方法的個數，可以將數組相鄰兩數交換，要求交換的次數必須最少。其實只要不重複交換兩個元素，交換的次數就是最少的。知道這一點後就可以直接回溯了。

AC的代碼如下：