$ Line [1] = intval ($ line [1]); // What does this write mean?

$ Line [1] intval ($ line [1]); what does this write mean?

   Bob's Auto Parts - Customer OrdersBob's Auto PartsCustomer Orders
 No orders pending.          Please try again later.
";  }  echo "
 
 
  
  \n";  echo "
  
  
     "; for ($i=0; $i<$number_of_orders; $i++) { //split up each line $line = explode("\t", $orders[$i]); // keep only the number of items ordered $line[1] = intval($line[1]); $line[2] = intval($line[2]); $line[3] = intval($line[3]); // output each order echo " 
   "; } echo " 
  
 
   
 
    
Order Date
 
    
Tires
 
    
Oil
 
    
Spark Plugs
 
    
Total
 
    
Address
 
   
 
   
 
   
 
    
".$line[0]."
 
    
".$line[1]."
 
    
".$line[2]."
 
    
".$line[3]."
 
    
".$line[4]."
 
    
".$line[5]."
 
   
 
 
";?>

$ Line [1] = intval ($ line [1]); // What does this write mean? The intval manual describes how intval returns the integer value of the variable var by using a specific hexadecimal conversion (decimal by default. But what is the role of assigning this integer value to $ line [1?

Reply to discussion (solution)

Intval () variable to integer type $ line [1] = intval ($ line [1]); $ line [2] = intval ($ line [2]); $ line [3] = intval ($ line [3]); convert to an integer type variable and recombine the array $ line. you can also, assign a value to the variable $ line_a = intval ($ line [1]); $ line_ B = intval ($ line [2]); $ line_c = intval ($ line [3]); then, your template shows that the corresponding changes are required.

$ Line [1] = intval ($ line [1]);
Make sure that the final value of $ line [1] is an integer.

What's more, the original author has already explained
38 rows have keep only the number of items ordered