. NET Surface Question series (14) Distributed lock

How to resolve a distributed lock timeout problem

We can let the thread that gets the lock open a daemon thread to "power" the lock that is about to expire

When a 29-second elapsed, thread A is not finished, this time the daemon executes the expire instruction and "renews" the lock for 20 seconds. The daemon thread executes from the 29th second, once every 20 seconds.

When thread a finishes performing a task, the daemon thread is explicitly turned off.

In another case, if node 1 suddenly loses power, the daemon thread will stop because thread A and the daemon thread are in the same process. When the lock expires, no one gives it a life, and it automatically releases it.

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. NET Surface Question series (14) Distributed lock