A noteworthy issue in java-difference between class member initialization and variable Initialization

Source: Internet
Author: User

1. code1

Class Change {int x;} public class JavaTest1 {public static void main (String [] agrs) {Change c = new Change (); System. out. println ("The value of c is" + c. x );}}

2. code2

Public class JavaTest1 {public static void main (String [] agrs) {int a; System. out. println ("The value of c is" + );}}

3. Analysis

Results In 1 are completely different from those in 2. Class Members in 1 are initialized to 0 when using the new function, although they are not displayed and initialized through objects, in 2, variable a is only a reference to an integer variable, so an error is reported.

Contact Us

The content source of this page is from Internet, which doesn't represent Alibaba Cloud's opinion; products and services mentioned on that page don't have any relationship with Alibaba Cloud. If the content of the page makes you feel confusing, please write us an email, we will handle the problem within 5 days after receiving your email.

If you find any instances of plagiarism from the community, please send an email to: info-contact@alibabacloud.com and provide relevant evidence. A staff member will contact you within 5 working days.

A Free Trial That Lets You Build Big!

Start building with 50+ products and up to 12 months usage for Elastic Compute Service

  • Sales Support

    1 on 1 presale consultation

  • After-Sales Support

    24/7 Technical Support 6 Free Tickets per Quarter Faster Response

  • Alibaba Cloud offers highly flexible support services tailored to meet your exact needs.