A summary of the methods of calculating the square root and number of the arithmetic in Python

This article mainly describes the Python to calculate the square root and the sum of the methods of the relevant data, the need for friends can refer to the following

One, the square root of arithmetic

A=x=int (Raw_input (' Enter a number: ')) if x >=: While a*a < x:a = a + if a*a! = X:print x, ' is not a perfect square ' els E:print aelse:print x, ' is a negative number '

Second, ask for approximate

Method One:

Pisor = []x=int (raw_input (' Enter a number: ')) i= while i<=x:if x%i = =:p Isor.append (i) i = i +print ' pisor: ', pisor

Method Two:

Pisor = []x=int (' Enter a number: ')] for I in range (, x+): if x%i = =:p Isor.append (i) # This line can also be changed to Pisor = Pisor + [i]p Rint ' pisor: ', pisor

Below you introduce the Python sqrt () function

Describe

The sqrt () method returns the square root of the number x.

Grammar

The following is the syntax for the sqrt () method:

Import mathmath.sqrt (x)

Note: sqrt () is not directly accessible, it needs to be imported into the math module and called by a static object.

Parameters

X--Numeric expression.

return value

Returns the square root of the number x.

Instance

The following shows an example of using the sqrt () method:

#!/usr/bin/pythonimport Math # This would import math Moduleprint "math.sqrt": ", math.sqrt (+) print" math.sqrt (7): ", Math.sqrt (7) print" Math.sqrt (Math.PI): ", Math.sqrt (Math.PI)

When the above instance is run, the output is:

MATH.SQRT (+): 10.0math.sqrt (7): 2.64575131106math.sqrt (Math.PI): 1.77245385091