Acm hdu 3354 probability one (simple question)

Probability one

Time Limit: 2000/1000 MS (Java/others) memory limit: 32768/32768 K (Java/Others)
Total submission (s): 301 accepted submission (s): 224

Problem descriptionnumber guessing is a popular game between elementary-school kids. teachers encourage pupils to play the game as it enhances their arithmetic skills, logical thinking, and following-up simple procedures. we think that, most probably, you too will master in few minutes. here's one example of how you too can play this game: ask a friend to think of a number, let's call it N0.
Then:
1. Ask your friend to compute n1 = 3 * N0 and to tell you if N1 is even or odd.
2. If N1 is even, ask your friend to compute n2 = N1/2. If, otherwise, N1 was odd then let your friend compute n2 = (N1 + 1)/2.
3. Now ask your friend to calculate N3 = 3 * N2.
4. ask your friend to tell you the result of N4 = N3/9. (n4 is the quotient of the division operation. in computer lingo, '/' is the integer-division operator .)
5. Now you can simply reveal the original number by calculating N0 = 2 * N4 If n1 was even, or N0 = 2 * N4 + 1 otherwise.
Here's an example that you can follow: If N0 = 37, then n1 = 111 which is odd. now we can calculate n2 = 56, N3 = 168, and N4 = 18, which is what your friend will tell you. doing the calculation 2 × N4 + 1 = 37 reveals N0.

Inputyour program will be tested on one or more test cases. Each test case is made of a single positive number (0 <N0 <1,000,000 ).
The last line of the input file has a single zero (which is not part of the test cases .)

Outputfor each test case, print the following line:
K. B q
Where k is the test case number (starting at one,) B is either 'even' or 'odd' (without the quotes) depending on your friend's answer in step 1. Q is your friend's answer to step 4.
Note: There is a blank space before B.

Sample input37
38
0

Sample output1. odd 18
2. Even 19

Source2009 anarc

Recommendlcy

 # Include  <  Stdio. h  >  
  Int  Main ()
{
  Int  N0;
  Int  Icase  =  0  ;
  While  (Scanf ( "  % D  "  ,  &  N0), N0)
{
Icase  ++  ;
Printf (  "  % D.  "  , Icase );
  If  (N0  %  2  = 0  )
Printf (  "  Even % d \ n  "  , N0  /  2  );
  Else   
Printf (  "  Odd % d \ n  "  , (N0  -  1 )  /  2  );
}
  Return     0  ;
}