Adjust the array order so that the odd digits are preceded by even numbers

Title: Enter an array of integers to achieve a cold and cold adjustment of the order of the numbers in the book group so that all the odd digits are in the first half of the array, and all the even digits are in the second half of the array.

Idea: This topic requires technology to be placed in the first half of the array, even in the second half of the array, so all the odd numbers should be in front of even numbers. In other words, when we scan this array, if we find that even numbers are in front of the odd number, we can exchange their order, and then we will meet the requirements after the exchange.

So we can maintain two pointers, the first pointer to the first number of the array when initialized, he moves backwards, the second pointer initializes to the last digit of the array, and he moves forward only. Before the two pointers meet, the first pointer is always in front of the second pointer. If the number that the first pointer points to is even, and the second pointer points to an odd number, we swap the two numbers.

 Public classorder{ Public voidGetOrder (int[] Array) {        intBegin = 0; intEnd = Array.length-1; if(array==NULL|| array.length==0)return;  while(begin<end) {             while(Begin<end & (array[begin]&1)!=0) {begin++; }             while(Begin<=end & (array[end]&1) ==0) {End--; }            if(begin<end) {                inttemp =Array[end]; Array[end]=Array[begin]; Array[begin]=temp; }        }    }     Public Static voidMain (string[] args) {int[] Array = {4,2,6,1,3,5}; Order o=NewOrder ();        O.getorder (array);  for(inti=0;i<array.length;i++) {System.out.println (array[i]); }    }}

Adjust the array order so that the odd digits are preceded by even numbers