Realization function: Find out two-dimensional convex hull of a pair of scattered points in the plane (see Codevs 1298)
It's an amazing algorithm--sort the points by the coordinates, then turn left as we know it, find the convex hull of the half, and then turn to the other side of the convex bag.
I used to be because of the idea of one step, so every time I kneel very miserable (hansbug: In fact, this is the first time in my life a-drop convex bag problem)
And then nothing else, is the basic idea of convex hull
(By the way, the output convex hull circumference C and area s, praise like a tide oh)
1 typeArr=Array[0..100005] ofLongint;2 var3 I,j,k,l,m,n,m1,m2:longint;4A:Array[0..100005,1..2] ofLongint;5 b,c,d:arr;ans,are:extended;6 procedureSwapvarx,y:longint);7 varZ:longint;8 begin9z:=x;x:=y;y:=Z;Ten End; One proceduresort (l,r:longint); A varI,j,x,y:longint; - begin -i:=l;j:=r;x:=a[(L+r)Div 2,1];y:=a[(L+r)Div 2,2]; the Repeat - while(A[i,1]<X)or(A[i,1]=X) and(A[i,2]<y)) DoInc (i); - while(A[j,1]>X)or(A[j,1]=X) and(A[j,2]>y)) DoDec (j); - ifI<=j Then + begin -Swap (A[i,1],a[j,1]); +Swap (A[i,2],a[j,2]); A Inc (I);d EC (j); at End; - untilI>J; - ifI<r Thensort (i,r); - ifL<j Thensort (l,j); - End; - functionRight (X1,y1,x2,y2:longint): boolean; in begin -Exit ((X1*y2) > (x2*y1)); to End; + functionTrip (X1,y1,x2,y2,x3,y3:longint): boolean; - begin theExit (Right (x2-x1,y2-y1,x3-x2,y3-y2)); * End; $ functionCheck (X,y,z:longint): boolean;Panax Notoginseng begin -Exit (Trip (A[x,1],a[x,2],a[y,1],a[y,2],a[z,1],a[z,2])); the End; + procedureDoitvarB:arr;varm:longint); A begin theb[1]:=d[1];b[2]:=d[2];j:=2; + fori:=3 toN Do - begin $ while(j>1) and not(Check (b[j-1],b[j],d[i])) DoDec (j); $Inc (J); b[j]:=D[i]; - End; -m:=J; the End; - beginWuyi READLN (n); the fori:=1 toN DoREADLN (A[i,1],a[i,2]); -Sort1, n); j:=1; Wu fori:=2 toN Do//Go heavy - begin About if(A[i,1]<>a[j,1])or(A[i,2]<>a[j,2]) Then $ begin - Inc (J); -A[j,1]:=a[i,1];a[j,2]:=a[i,2]; - End; A End; +n:=J; the//Convex bag - fori:=1 toN Dod[i]:=I;doit (B,M1); $ fori:=1 toN Dod[i]:=n+1-I;doit (c,m2); the//two halves of integration the fori:=1 toM1 Dod[i]:=B[i]; the fori:=2 toM2 DoD[i+m1-1]:=C[i]; theStart calculating perimeter +Area -m:=m1+m2-2; ans:=0; are:=0; in fori:=1 toM DoAns:=ans+sqrt (Sqr (a[d[i),1]-a[d[i+1],1]) +sqr (A[d[i],2]-a[d[i+1],2])); //Perimeter the fori:=1 toM DoAre:=are+a[d[i],1]*a[d[i+1],2]-a[d[i],2]*a[d[i+1],1]; //Area theAre:=abs (IS)/2; AboutWriteln ('Convex Hull:'); the fori:=1 toM DoWriteln (A[d[i],1],' ', A[d[i],2]); theWriteln ('C =', ans:0:1); theWriteln ('S =', is:0:1); + Readln; - End.
Algorithm template--Computational Geometry 2 (two-dimensional convex hull--andrew algorithm)