An odd number within 100 of the job.

Ideas:

• First, 1 to 100 of the number, output.
• Use "%" to get the remainder of the value (0 or 1).

Start with your own approach:

1 s1 = 12 while s1<101:3     print(S1)4     S1 + = 15if s1% 2 = = 0; 6     Print (S1) 7      Break

5th line error. If syntax uses Error!
After watching the video, modify the code

S1 = 1 while s1<101:    = s1% 2    if s2 = =1        :print(S1)     Else:        pass #这里必须要定义, otherwise syntax error.     

An odd number within 100 of the job.