Ask a server log for the regular how to write

2013-06-23 04:33:51 w3svc1539885 198.56.185.162 get/robots.txt-80-66.249.75.65 mozilla/5.0+ (compatible;+googlebot/ 2.1;++http://www.google.com/bot.html) 404 0 2

I would like to match the date 2013-06-23/time 04:33:51/server ip198.56.185.162/file address robots.txt/spider ip66.249.75.65/Spider information mozilla/5.0+ (compatible; +googlebot/2.1;++http://www.google.com/bot.html)/Status code 404 0 2/, how exactly does this match?

Reply to discussion (solution)

It's best to give a specific example, and then show the results you expect, and your question indicates that you don't understand

It's best to give a specific example, and then show the results you expect, and your question indicates that you don't understand
The code is a specific example, I want to take the value of the following, just want to write a sentence regular match, with Pregmatch this generation of an array and then I do something else.

I think the format of this date should be fixed, you can split them by a space, for example

$log = ' 2013-06-23 04:33:51 w3svc1539885 198.56.185.162 get/robots.txt-80-66.249.75.65 mozilla/5.0+ (COMPATIBLE;+GOOGL ebot/2.1;++http://www.google.com/bot.html) 404 0 2 '; Var_dump (Explode (", $log)); /**array {  [0]=>  string (Ten) "2013-06-23"  [1]=>  string (8) "04:33:51"  [2]=>  String ("w3svc1539885"  [3]=> string "  198.56.185.162"  [4]=>  string (3) "GET"  [5]= >  string (one) "/robots.txt"  [6]=>  string (1) "-"  [7]=>  string (2) "  [8]= >  string (1) "-"  [9]=>  string (66.249.75.65) "  [10]=> string"  mozilla/5.0+ (compatible;+googlebot/2.1;++http://www.google.com/bot.html) "  [11]=>  string (3)" 404 "  [12]= >  string (1) "0"  [13]=>  string (1) "2"}*/

I think the format of this date should be fixed, you can split them by a space, for example

$log = ' 2013-06-23 04:33:51 w3svc1539885 198.56.185.162 get/robots.txt-80-66.249.75.65 mozilla/5.0+ (COMPATIBLE;+GOOGL ebot/2.1;++http://www.google.com/bot.html) 404 0 2 '; Var_dump (Explode (", $log)); /**array {  [0]=>  string (Ten) "2013-06-23"  [1]=>  string (8) "04:33:51"  [2]=>  String ("w3svc1539885"  [3]=> string "  198.56.185.162"  [4]=>  string (3) "GET"  [5]= >  string (one) "/robots.txt"  [6]=>  string (1) "-"  [7]=>  string (2) "  [8]= >  string (1) "-"  [9]=>  string (66.249.75.65) "  [10]=> string"  mozilla/5.0+ (compatible;+googlebot/2.1;++http://www.google.com/bot.html) "  [11]=>  string (3)" 404 "  [12]= >  string (1) "0"  [13]=>  string (1) "2"}*/

I think the format of this date should be fixed, you can split them by a space, for example

$log = ' 2013-06-23 04:33:51 w3svc1539885 198.56.185.162 get/robots.txt-80-66.249.75.65 mozilla/5.0+ (COMPATIBLE;+GOOGL ebot/2.1;++http://www.google.com/bot.html) 404 0 2 '; Var_dump (Explode (", $log)); /**array {  [0]=>  string (Ten) "2013-06-23"  [1]=>  string (8) "04:33:51"  [2]=>  String ("w3svc1539885"  [3]=> string "  198.56.185.162"  [4]=>  string (3) "GET"  [5]= >  string (one) "/robots.txt"  [6]=>  string (1) "-"  [7]=>  string (2) "  [8]= >  string (1) "-"  [9]=>  string (66.249.75.65) "  [10]=> string"  mozilla/5.0+ (compatible;+googlebot/2.1;++http://www.google.com/bot.html) "  [11]=>  string (3)" 404 "  [12]= >  string (1) "0"  [13]=>  string (1) "2"}*/

But the server log is not every line is like this, there are many # beginning, so just want to do a regular filter out the other format.

This point can't be wasted.

Log files are generally very large
You need to read through the loop in a row, split into arrays

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