This question ... Feel that offline and online code is almost as difficult (Pb_ds don't talk).
Offline, is to put all the queries according to the order of W, and then one side kruskal+ the balance tree heuristic merge side to answer the question.
It's not hard to write online. First Kruskal the refactoring tree (the Kruskal is the kind that does not merge by rank and adds a virtual point ...), then the points that can be reached at each point must be in a subtree. The DFS sequence of the subtree is continuous, so the DFS sequence can be built as a tree to find the interval k large. And because only the point of the leaf node is meaningful, so you can only build the tree of the DFS sequence of the leaves. When querying, multiply jumps to the top of the w<= asking for the W Point and then the Chairman tree is ready.
In fact, the tree split jump father can also, first jump the whole chain, the whole chain is not moving in the last chain of two points, also O (Logn). But it may be too weak, two points write hung, the result wa to die ... Helpless to rewrite it again with multiplication.
Limited time 20s, the result I ran 19.8s, this speed is really touching ...
Also, the copy of the A began to forget + 1, a lesson, a false death ...
1 /**************************************************************2 problem:35513 User:hzoier4 language:c++5 result:accepted6 time:19800 Ms7 memory:114432 KB8 ****************************************************************/9#include <cstdio>Ten#include <cstring> One#include <algorithm> A using namespacestd; - Const intmaxn=200010, maxe=500010; - structedge{ the int from, to,w; - BOOL operator< (ConstEdge &e)Const{returnw<E.W;} -}e[maxe+MAXN]; - voidKruskal (); + intFindrootint); - voidMergeset (int,int); + voidDfsint); A voidBuildint,int,int&,int); at voidQueryint,int,int,int); - intsm[maxn<<5],lc[maxn<<5],rc[maxn<<5],root[maxn],tree_cnt=0; - intn,m=0, m,q,h[maxn],a[maxn],cnt,prt[maxn],w[maxn],f[maxn][ -],ch[maxn][2],l[maxn],r[maxn],pr=0, X,d,k,ans; - intMain () { -scanf"%d%d%d",&n,&m,&q); - while((1<<M) < (n<<1)) m++; in for(intI=1; i<=n;i++) scanf ("%d",&h[i]); -Copy (H +1, h+n+1, A +1); toSort (A +1, a+n+1); + for(intI=1; i<=n;i++) H[i]=lower_bound (A +1, a+n+1, H[i])-A; - for(intI=1; i<=m;i++) scanf ("%d%d%d", &e[i]. from,&e[i].to,&E[I].W); the for(intI=2; i<=n;i++){ *E[++M]. from=1; $e[m].to=i;Panax NotoginsengE[m].w=~ (1<< to); - } theCnt=N; + Kruskal (); A DFS (CNT); the for(intj=1; j<=m;j++) for(intI=1; i<=cnt;i++) f[i][j]=f[f[i][j-1]][j-1]; + while(q--){ -scanf"%d%d%d",&x,&d,&k); $ if(ans!=-1) {x^=ans;d^=ans;k^=ans;} $ for(intj=m;j!=-1; j--)if(F[x][j]&&w[f[x][j]]<=d) x=F[x][j]; -Query1, n,root[r[x]],root[l[x]-1]); -printf"%d\n", ans); the } - return 0;Wuyi } the voidKruskal () { - for(intI=1; i<=n;i++) prt[i]=i; WuStable_sort (e+1, e+m+1); - for(intI=1; i<=m;i++)if(Findroot (e[i). from)!=Findroot (e[i].to)) { Aboutcnt++; $prt[cnt]=CNT; -w[cnt]=E[I].W; -ch[cnt][0]=findroot (E[i]. from); -ch[cnt][1]=Findroot (e[i].to); AMergeset (E[i]. from, CNT); + Mergeset (e[i].to,cnt); the } - } $ intFindrootintx) {returnPrt[x]==x?x: (prt[x]=Findroot (prt[x]));} the voidMergeset (intXintY) {prt[findroot (x)]=findroot (y);} the voidDfsintx) { the if(ch[x][0]){ thef[ch[x][0]][0]=f[ch[x][1]][0]=x; -DFS (ch[x][0]); inDFS (ch[x][1]); thel[x]=l[ch[x][0]]; ther[x]=r[ch[x][1]]; About } the Else{ thek=H[x]; theBuild1, n,root[pr+1],ROOT[PR]); +l[x]=r[x]=++PR; - } the }Bayi voidBuildintLintRint&rt,intPR) { thesm[rt=++tree_cnt]=sm[pr]+1; the if(L==R)return; -lc[rt]=lc[pr];rc[rt]=RC[PR]; - intMid= (l+r) >>1; the if(k<=mid) Build (L,MID,LC[RT],LC[PR]); the ElseBuild (mid+1, R,RC[RT],RC[PR]); the } the voidQueryintLintRintRtintPR) { - if(sm[rt]-sm[pr]<k) { theans=-1; the return; the }94 if(l==R) { theans=A[l]; the return; the }98 intMid= (l+r) >>1; About if(K<=SM[RC[RT]]-SM[RC[PR]]) query (mid+1, R,RC[RT],RC[PR]); - Else{101k-=sm[rc[rt]]-SM[RC[PR]];102 query (L,MID,LC[RT],LC[PR]);103 }104}
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The end and the beginning, there is always one waiting for you.
bzoj3551 Peaks Enhanced Edition