C # Winform calls the JS method and uses md5 of the QQ logon password as an example,

C # Winform calls the JS method and uses md5 of the QQ logon password as an example,

C # Call Code

ScriptControlClass js = new ScriptControlClass (); js. language = "JScript"; js. addCode (textBox2.Text); // JS code string result = null; result = js. eval (textBox1.Text ). toString (); // call the MessageBox function. show (result );

MD5 JS Code

function md5js(pass, code, uin) {var I = hexchar2bin(md5(pass));var H = md5(I + uin);var G = md5(H + code.toUpperCase());return G}var hexcase = 1;var b64pad = "";var chrsz = 8;var mode = 32;function md5(A) {return hex_md5(A)}function hex_md5(A) {return binl2hex(core_md5(str2binl(A), A.length * chrsz))}function str_md5(A) {return binl2str(core_md5(str2binl(A), A.length * chrsz))}function hex_hmac_md5(A, B) {return binl2hex(core_hmac_md5(A, B))}function b64_hmac_md5(A, B) {return binl2b64(core_hmac_md5(A, B))}function str_hmac_md5(A, B) {return binl2str(core_hmac_md5(A, B))}function core_md5(K, F) {K[F >> 5] |= 128 << ((F) % 32);K[(((F + 64) >>> 9) << 4) + 14] = F;var J = 1732584193;var I = -271733879;var H = -1732584194;var G = 271733878;for (var C = 0; C < K.length; C += 16) {    var E = J;    var D = I;    var B = H;    var A = G;    J = md5_ff(J, I, H, G, K[C + 0], 7, -680876936);    G = md5_ff(G, J, I, H, K[C + 1], 12, -389564586);    H = md5_ff(H, G, J, I, K[C + 2], 17, 606105819);    I = md5_ff(I, H, G, J, K[C + 3], 22, -1044525330);    J = md5_ff(J, I, H, G, K[C + 4], 7, -176418897);    G = md5_ff(G, J, I, H, K[C + 5], 12, 1200080426);    H = md5_ff(H, G, J, I, K[C + 6], 17, -1473231341);    I = md5_ff(I, H, G, J, K[C + 7], 22, -45705983);    J = md5_ff(J, I, H, G, K[C + 8], 7, 1770035416);    G = md5_ff(G, J, I, H, K[C + 9], 12, -1958414417);    H = md5_ff(H, G, J, I, K[C + 10], 17, -42063);    I = md5_ff(I, H, G, J, K[C + 11], 22, -1990404162);    J = md5_ff(J, I, H, G, K[C + 12], 7, 1804603682);    G = md5_ff(G, J, I, H, K[C + 13], 12, -40341101);    H = md5_ff(H, G, J, I, K[C + 14], 17, -1502002290);    I = md5_ff(I, H, G, J, K[C + 15], 22, 1236535329);    J = md5_gg(J, I, H, G, K[C + 1], 5, -165796510);    G = md5_gg(G, J, I, H, K[C + 6], 9, -1069501632);    H = md5_gg(H, G, J, I, K[C + 11], 14, 643717713);    I = md5_gg(I, H, G, J, K[C + 0], 20, -373897302);    J = md5_gg(J, I, H, G, K[C + 5], 5, -701558691);    G = md5_gg(G, J, I, H, K[C + 10], 9, 38016083);    H = md5_gg(H, G, J, I, K[C + 15], 14, -660478335);    I = md5_gg(I, H, G, J, K[C + 4], 20, -405537848);    J = md5_gg(J, I, H, G, K[C + 9], 5, 568446438);    G = md5_gg(G, J, I, H, K[C + 14], 9, -1019803690);    H = md5_gg(H, G, J, I, K[C + 3], 14, -187363961);    I = md5_gg(I, H, G, J, K[C + 8], 20, 1163531501);    J = md5_gg(J, I, H, G, K[C + 13], 5, -1444681467);    G = md5_gg(G, J, I, H, K[C + 2], 9, -51403784);    H = md5_gg(H, G, J, I, K[C + 7], 14, 1735328473);    I = md5_gg(I, H, G, J, K[C + 12], 20, -1926607734);    J = md5_hh(J, I, H, G, K[C + 5], 4, -378558);    G = md5_hh(G, J, I, H, K[C + 8], 11, -2022574463);    H = md5_hh(H, G, J, I, K[C + 11], 16, 1839030562);    I = md5_hh(I, H, G, J, K[C + 14], 23, -35309556);    J = md5_hh(J, I, H, G, K[C + 1], 4, -1530992060);    G = md5_hh(G, J, I, H, K[C + 4], 11, 1272893353);    H = md5_hh(H, G, J, I, K[C + 7], 16, -155497632);    I = md5_hh(I, H, G, J, K[C + 10], 23, -1094730640);    J = md5_hh(J, I, H, G, K[C + 13], 4, 681279174);    G = md5_hh(G, J, I, H, K[C + 0], 11, -358537222);    H = md5_hh(H, G, J, I, K[C + 3], 16, -722521979);    I = md5_hh(I, H, G, J, K[C + 6], 23, 76029189);    J = md5_hh(J, I, H, G, K[C + 9], 4, -640364487);    G = md5_hh(G, J, I, H, K[C + 12], 11, -421815835);    H = md5_hh(H, G, J, I, K[C + 15], 16, 530742520);    I = md5_hh(I, H, G, J, K[C + 2], 23, -995338651);    J = md5_ii(J, I, H, G, K[C + 0], 6, -198630844);    G = md5_ii(G, J, I, H, K[C + 7], 10, 1126891415);    H = md5_ii(H, G, J, I, K[C + 14], 15, -1416354905);    I = md5_ii(I, H, G, J, K[C + 5], 21, -57434055);    J = md5_ii(J, I, H, G, K[C + 12], 6, 1700485571);    G = md5_ii(G, J, I, H, K[C + 3], 10, -1894986606);    H = md5_ii(H, G, J, I, K[C + 10], 15, -1051523);    I = md5_ii(I, H, G, J, K[C + 1], 21, -2054922799);    J = md5_ii(J, I, H, G, K[C + 8], 6, 1873313359);    G = md5_ii(G, J, I, H, K[C + 15], 10, -30611744);    H = md5_ii(H, G, J, I, K[C + 6], 15, -1560198380);    I = md5_ii(I, H, G, J, K[C + 13], 21, 1309151649);    J = md5_ii(J, I, H, G, K[C + 4], 6, -145523070);    G = md5_ii(G, J, I, H, K[C + 11], 10, -1120210379);    H = md5_ii(H, G, J, I, K[C + 2], 15, 718787259);    I = md5_ii(I, H, G, J, K[C + 9], 21, -343485551);    J = safe_add(J, E);    I = safe_add(I, D);    H = safe_add(H, B);    G = safe_add(G, A)}if (mode == 16) {    return Array(I, H)} else {    return Array(J, I, H, G)} }function md5_cmn(F, C, B, A, E, D) {return safe_add(bit_rol(safe_add(safe_add(C, F), safe_add(A, D)), E), B)}function md5_ff(C, B, G, F, A, E, D) {return md5_cmn((B & G) | ((~B) & F), C, B, A, E, D)}function md5_gg(C, B, G, F, A, E, D) {return md5_cmn((B & F) | (G & (~F)), C, B, A, E, D)}function md5_hh(C, B, G, F, A, E, D) {return md5_cmn(B ^ G ^ F, C, B, A, E, D)}function md5_ii(C, B, G, F, A, E, D) {return md5_cmn(G ^ (B | (~F)), C, B, A, E, D)}function core_hmac_md5(C, F) {var E = str2binl(C);if (E.length > 16) {    E = core_md5(E, C.length * chrsz)}var A = Array(16),D = Array(16);for (var B = 0; B < 16; B++) {    A[B] = E[B] ^ 909522486;    D[B] = E[B] ^ 1549556828}var G = core_md5(A.concat(str2binl(F)), 512 + F.length * chrsz);return core_md5(D.concat(G), 512 + 128)}function safe_add(A, D) {var C = (A & 65535) + (D & 65535);var B = (A >> 16) + (D >> 16) + (C >> 16);return (B << 16) | (C & 65535)}function bit_rol(A, B) {return (A << B) | (A >>> (32 - B))}function str2binl(D) {var C = Array();var A = (1 << chrsz) - 1;for (var B = 0; B < D.length * chrsz; B += chrsz) {    C[B >> 5] |= (D.charCodeAt(B / chrsz) & A) << (B % 32)}return C}function binl2str(C) {var D = "";var A = (1 << chrsz) - 1;for (var B = 0; B < C.length * 32; B += chrsz) {    D += String.fromCharCode((C[B >> 5] >>> (B % 32)) & A)}return D}function binl2hex(C) {var B = hexcase ? "0123456789ABCDEF": "0123456789abcdef";var D = "";for (var A = 0; A < C.length * 4; A++) {    D += B.charAt((C[A >> 2] >> ((A % 4) * 8 + 4)) & 15) + B.charAt((C[A >> 2] >> ((A % 4) * 8)) & 15)}return D}function binl2b64(D) {var C = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";var F = "";for (var B = 0; B < D.length * 4; B += 3) {    var E = (((D[B >> 2] >> 8 * (B % 4)) & 255) << 16) | (((D[B + 1 >> 2] >> 8 * ((B + 1) % 4)) & 255) << 8) | ((D[B + 2 >> 2] >> 8 * ((B + 2) % 4)) & 255);    for (var A = 0; A < 4; A++) {        if (B * 8 + A * 6 > D.length * 32) {            F += b64pad        } else {            F += C.charAt((E >> 6 * (3 - A)) & 63)        }     } }return F}function hexchar2bin(str) {var arr = [];for (var i = 0; i < str.length; i = i + 2) {    arr.push("\\x" + str.substr(i, 2))}arr = arr.join("");eval("var temp = '" + arr + "'");return temp}

 

C language ^ how to use

A1 = 0x01; // 0000 0001
A2 = 0x00; // 0000 0000
A3 = 0x03; // 0000 0011
A4 = 0x02; // 0000 0010

B1 = a1 ^ a2; // 0000 0001
B2 = a1 ^ a3; // 0000 0010
B3 = a1 ^ a4; // 0000 0011

^ XOR operator. The bitwise value is 0 and the difference is 1. See the example above.

//
Examples of simple and practical problems:
====================================
======= A ======= B =========
There are two circuits on the top. The two switches are a and B respectively. The opening status is \ [1], and the closing status is/[0].
If both circuits are enabled or disabled.
If a turns on [1], B turns off [0], and circuit 1 Powers on
=====================
If a disables [0], B enables [1], and circuit 2 powers on.
====================================
In summary, the circuit fails in the and B states simultaneously [0]. When a and B are different, the power is charged [1].

C language ^ how to use

A1 = 0x01; // 0000 0001
A2 = 0x00; // 0000 0000
A3 = 0x03; // 0000 0011
A4 = 0x02; // 0000 0010

B1 = a1 ^ a2; // 0000 0001
B2 = a1 ^ a3; // 0000 0010
B3 = a1 ^ a4; // 0000 0011

^ XOR operator. The bitwise value is 0 and the difference is 1. See the example above.

//
Examples of simple and practical problems:
====================================
======= A ======= B =========
There are two circuits on the top. The two switches are a and B respectively. The opening status is \ [1], and the closing status is/[0].
If both circuits are enabled or disabled.
If a turns on [1], B turns off [0], and circuit 1 Powers on
=====================
If a disables [0], B enables [1], and circuit 2 powers on.
====================================
In summary, the circuit fails in the and B states simultaneously [0]. When a and B are different, the power is charged [1].