C language does not look how to save, only to see how to read, short bytes between long bytes of conversion

Don't look how to save, only see how to read

e.g. int a = 010; 8 with 8 binary memory
int b = 8;//8 is stored in 10
printf ("%d%d\n", A, b); A and B are printed in decimal 8.
printf ("%o%o\n", A, b); A and B are 10 in 8.

Char still occupies 1 bytes in the C language.

' A ' is 4 bytes, char _a = ' a '
How do I assign a value of 4 bytes to 1 bytes? to truncate. The high position cannot be saved and discarded.
0000 0000 0000 0000 0001 0000 0100 0001 ' A '
Truncation, starting from the bottom of the deposit, the high position is discarded.
0100 0001

Char a=1;
Short b=a; A bit extension occurs when the char is stored in short.
0000 0001
Bit extension
0000 0000 0000 0001
Positive 0, negative complement 1

Char A=-1
Short b=a;
1111 1111 (-1 complement)
1111 1111 1111 1111

The operation between variables in C language
1. Short byte to Long byte
2, signed to the non-symbol on par.
3, integral type to floating point.
4, single-precision to double-precision on par.

C language does not look how to save, only to see how to read, short bytes between long bytes of conversion