Data structure--sort--simple sort

Source: Internet
Author: User

1 /*Insert Sort--is the basic sort of the performance is better (more suitable for basic ordered sort)2 * Sort ideas: A sequence, the front is ordered, the back is unordered, take out an element to insert into the already ordered3 * Part (here involves moving the operation)--Find the position first, then move4 * Features: A trip to sort down the position of each element may not be fixed5 * Complexity of Time: O (N2)6 * sequencing Stability: Stable7 * Usage Scenario: The data is basically ordered in the case8  * */9  Public classTestinsertsort {Ten  One      Public Static voidMain (string[] args) { A         int[] List1 = {10,8,9,7}; - Insertsort (list1); -          for(inti = 0; i < list1.length; i++){ theSystem.out.print (List1[i] + ""); -         } -  -     } +      -      Public Static voidInsertsort (int[] list) { +          for(inti = 1; I <list.length; i++){ A             //record values that are now being compared at             inttemp =List[i]; -             intj =i; -             //compare to the previous ordered section find location insert "satisfy >0 and smaller than previous element" -              while(J > 0 && list[j-1] >temp) { -LIST[J] = list[j-1];//move to the right . -j--; in             } -LIST[J] =temp; to         } +     } -  the}

1 /*Bubble Sort--a simple sort2 * Thought: Is the comparison of each of the two adjacent elements-the interchange until the end of the sequencing, to determine the largest element3 * Specific implementation: Nested Loops required4 * Outer loop: Control sort pass number--n-15 * Inner Loop: Control the number of comparisons per trip n-1/n-2 ....6 * Time complexity of bubble sort: O (N2)--compare + swap7 * Sort Stability: Refers to elements that have the same value when the relative position remains unchanged after sorting8 * The essence is that the condition is greater than and not greater than or equal to9  * */Ten  Public classTestbubblesort { One  A      Public Static voidMain (string[] args) { -         int[] list = {10, 8,7,9,2,3,1,0}; -         int[] List1 =Bubblesort (list); the          for(inti = 0; i < list1.length; i++){ -System.out.print (List1[i] + ""); -         } -     } +      -      Public Static int[] Bubblesort (int[] list) { +         //number of times the external loop control is sorted A          for(inti = 1; i < list.length; i++){ at             //internally compare the number of times per trip -              for(intj = 0; J <list.length-i; J + + ){ -                 if(List[j] > List[j+1]) {//Guaranteed sequencing Stability -                     inttemp =List[j]; -LIST[J] = list[j+1]; -LIST[J+1] =temp; in                      -                 } to             } +         } -         returnlist; the     } *      $     Panax Notoginseng  -}

1 /*Select Sort--a certain improvement in bubble sort, which reduces the number of good times2 * Basic idea: Compare the first element with all subsequent elements to find the smallest element with the first interchange3 * Complete the order once, then find the second small, etc.4 * Specific implementation: Nested Loops (outer control sort pass number, internal control exchange number)5 * Select time complexity for sorting: O (N2)6 * Stability of sequencing: stable7 * Usage Scenario: Small amount of data8  * */9  Public classTestselectsort {Ten  One      Public Static voidMain (string[] args) { A         int[] List1 = {10,8,0,7,9,7,6,5,4}; - Selectsort (list1); -          for(inti = 0; i < list1.length; i++){ theSystem.out.print (List1[i] + ""); -         } -     } -      +     //and orderly not participating in the comparison "reduce the number of good times" -      Public Static voidSelectsort (int[] list) { +          for(inti = 0; i < list.length-1; i++){ A              for(intj = i + 1; J < List.length; J + +){ at                 if(List[i] >List[j]) { -                     inttemp =List[i]; -List[i] =List[j]; -LIST[J] =temp; -                 } -             } in         } -     } to  +}

Data structure--sort--simple sort

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