Error generating Swagger server (Python Flask) from Swagger Editor

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Http://stackoverflow.com/questions/36416679/error-generating-swagger-server-python-flask-from-swagger-editor I ' ve used the Swagger Editor to manually generate my Swagger spec file and generated the files for a Python Flask server. Following the README I installed connexion, but if I run python app.py I get the error:ValueError:need more than 1 value to u Npack. Any ideas? Full stack trace below: NoHandlers could be foundForLogger"Connexion.api"Traceback (Most recent): File "App.py",Line5, Inch <Module>App.Add_api(' Swagger.yaml ') File "/library/frameworks/python.framework/versions/2.7/lib/python2.7/site-packages/connexion/app.py",Line144, InchAdd_api Debug=Self.Debug) File "/library/frameworks/python.framework/versions/2.7/lib/python2.7/site-packages/connexion/api.py",Line127, Inch__init__ Self.Add_paths() File "/library/frameworks/python.framework/versions/2.7/lib/python2.7/site-packages/connexion/api.py",Line198, InchAdd_paths Six.Reraise(*Sys.Exc_info()) File "/library/frameworks/python.framework/versions/2.7/lib/python2.7/site-packages/connexion/api.py",Line187, InchAdd_paths Self.Add_operation(Method,Path,Endpoint,Path_parameters) File "/library/frameworks/python.framework/versions/2.7/lib/python2.7/site-packages/connexion/api.py",Line160, InchAdd_operation Resolver=Self.Resolver) File "/library/frameworks/python.framework/versions/2.7/lib/python2.7/site-packages/connexion/operation.py",Line168, Inch__INIT__ resolution=Resolver.Resolve(Self) File "/library/frameworks/python.framework/versions/2.7/lib/python2.7/site-packages/connexion/resolver.py",Line50, InchResolveReturn Resolution(Self.resolve_function_from_operation_id(operation_id),operation_id) File "/library/frameworks/python.framework/versions/2.7/lib/python2.7/site-packages/connexion/resolver.py",Line71, Inchresolve_function_from_operation_idReturnSelf.Function_resolver(operation_id file /library/ frameworks/python.framework/versions/2.7/lib/python2.7/site-packages/connexion/utils.py ",< Span class= "PLN" > line 106, in Get_function_from_name module_name, attr_path1 = Module_name., 1) Valueerror: need more than 1 value to unpack< /span> python flask swagger     share|improve This question          asked APR 5 at 3:36            tw1742         117211

1 please open a ticket via github.com/ Swagger-api/swagger-codegen/issues for tracking.                     – wing328                  APR 6 at 4:45                                                                                  Add a Comment |

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I ran into the as well. From what I see, the generated code from Swagger seems to assume you ' re using Python 3. While Connexion supports both Python 2.7 & 3.4+, it does need a __init__.py file in the generated python-flask-server/ base directory as we ll as inside the subdirectory to work for controllers/ Python 2.7 (implicit Namespace Packages were introduced in Python 3.3). If you create those 2 empty files through generating the code, things should work. If The Swagger generator wants to support Python 2.7 (since Connexion allows for it), it would just need to provide those Files as well.

Error generating Swagger server (Python Flask) from Swagger Editor