Fastjson meet the problem or project to optimize the problem, see source code can be solved

1: It feels like hell. General storage jsonobject fields are missing?

        Jsonobject object=new jsonobject ();        Map fields = new HashMap ();        Fields.put ("1", "1");        Object.put ("Fields", fields);        System.out.println (Object.ToString ());        Jsonobject newfields = Object.getjsonobject ("Fields");        Newfields.put ("2", 2);        TODO  serialized string not 2?!!        //See the source code can be known, when we use map as Jsonobject parsing, Fastjson will return a new object        System.out.println (Object.ToString ());

　　

Com.alibaba.fastjson.json#tojson (Java.lang.Object, com.alibaba.fastjson.serializer.SerializeConfig) Source:

public static object ToJSON (object javaobject, Serializeconfig config) {        if (Javaobject = = null) {            return Null;
   }        if (Javaobject instanceof JSON) {            return javaobject;        }        if (javaobject instanceof map) {            map<object, object> map = (Map<object, object>) javaobject; A new jsonobject was created to return the            jsonobject json = new Jsonobject (Map.size ());            For (Map.entry<object, object> entry:map.entrySet ()) {                Object key = Entry.getkey ();                String Jsonkey = typeutils.casttostring (key);                Object Jsonvalue = ToJSON (Entry.getvalue ());                Json.put (Jsonkey, Jsonvalue);            }            return JSON;        }

　　

2: When we use Jsonarray, sometimes it is possible to store a larger amount of data, but some scenarios need to be at the specified index at the insert operation, because the Jsonarray default underlying use of ArrayList storage, so there is a performance problem, So is it possible to use LinkedList? The answer can be:

Jsonarray arr = new Jsonarray (new LinkedList ());

　　

3: Can we replace the underlying stored ArrayList with LinkedList when we query the interface to get a jsonarray string to deserialize? Answer: Yes, modify the source code or add an overloaded method.

public static Jsonarray Parsearray (String text) {        if (text = = null) {            return null;        }        Defaultjsonparser parser = new Defaultjsonparser (text, parserconfig.getglobalinstance ());        Jsonarray Array;        Jsonlexer lexer = parser.lexer;        if (lexer.token () = = Jsontoken.null) {            lexer.nexttoken ();            Array = null;        } else if (lexer.token () = = jsontoken.eof) {            array = null;        } else {//            array = new Jsonarray (new ArrayList ());            array = new Jsonarray (new LinkedList ());            Parser.parsearray (array);            Parser.handleresovletask (array);        }        Parser.close ();        return array;    }

　　

Fastjson meet the problem or project to optimize the problem, see source code can be solved