Object-Oriented Programming-c++_ lesson 21 references

Data type & alias = object name;

1#include <iostream>2 using namespacestd;3 4 int* F (int*x)5 {6(*x) + +;7     returnx;8 }9 Ten int& G (int&x) One { AX + +; -     returnx; - } the  - intx; -  - int&h () + { -     intQ//!return Q +     returnx; A } at  - voidMain () - { -     intA =0; -Std::cout << a << std::endl;//0 -  inf (&a);//ugly, but clear. -Std::cout << a << std::endl;//1 to  +g (a);//clear, but covert, can modify a -Std::cout << a << std::endl;//2 the  *H () = -;//The return value is a reference, so you can do an lvalue $Std::cout << a << std::endl;//2Panax Notoginseng  -Std::cout << x << Std::endl;// - the  +System"Pause"); A}

You cannot declare a reference reference

You can declare a reference to a pointer, but you cannot declare a pointer-to-variable reference

int & * P;//illegal

int * & P1=p2;//ok

void f (int * & P);

P is a reference that references a pointer to type int

You can declare a pointer to a reference

Arrays without references (array elements cannot be references)

But you can reference an array

Object-Oriented Programming-c++_ lesson 21 references