Tomcat 5.5 connection pool configuration, how to make the project the default Project

You just need to add this between

CopyCode The Code is as follows: <context docbase = "C: /program files/Apache Software Foundation/tomcat5.5/webapps/fengyue "Path =" "DEBUG =" 0 "reloadable =" true "privileged =" true ">
<Resource Name = "Aaa/oracleds" type = "javax. SQL. datasource"
Password = "maxtie17061706"
Driverclassname = "oracle. JDBC. Driver. oracledriver"
Maxidle = "2"
Maxwait = "5000"
Username = "maxtie"
Url = "JDBC: oracle: thin: @ 192.168.0.13: 1521: MMIS"
Maxactive = "4"/>
</Context>

This is configured together with the connection pool for the default project. If you want to change the path, you just need to change the path.

If only the default project is configured:

Copy code The Code is as follows: <context docbase = "C: /program files/Apache Software Foundation/tomcat5.5/webapps/fengyue "Path =" "DEBUG =" 0 "reloadable =" true "privileged =" true "> </context>

This sentence is enough. The key is the path.

Finally, the test code must be run in the web project.

Copy code The Code is as follows: initialcontext CTX = new initialcontext ();
Datasource DS = (datasource) CTX. Lookup ("Java: COMP/ENV/AAA/oracleds ");
Conn = Ds. getconnection ();