Tutorial 11: Problem B: score type conversion, 11. problem
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Problem B: score type conversion Problem B: score class type conversion Time Limit: 3 Sec Memory Limit: 128 MB
Submit: 579 Solved: 431
[Submit] [Status] [Web Board] Description encapsulates a score class Fract to process score functions and operations. The following operations are supported: 1. constructor: input two parameters n and m, indicating n/m. The score is converted to the simplest score immediately during the constructor. 2. show () function: The score output is in the form of "a/B" or "-a/B". a and B are all unsigned integers. If a is 0 or B is 1, only the symbols and molecules are output, and "/" and denominator are not output. 3. double type conversion function: returns the decimal number by dividing the numerator by the denominator. Note: When the numerator is 0, do not output "-0" ----------------------------------------------------------------------you design a Fract class so that the main () function can be run and output properly. For the call format, see append. cc.
Input Multiple rows. Each row has two integers, the numerator and the denominator, respectively, until the end of EOF. The input denominator is not 0;
Each row of Output outputs a real number and a score, consistent with the input order. The real number is obtained by dividing the numerator by the denominator. The score is output in the simplest form, and the negative sign only appears at the beginning. If the denominator is 1 or the numerator is 0, only one integer is output, that is, the numerator part, there is no "/" or denominator.
Sample Input1 320-1580 150-9 16 612 16-33-486 110-10 Sample Output0.333333 1/3-1.33333-4/30. 533333 8/15-9-91 10.75 3/40. 6875 11/160. 545455 6/110 0 HINT Append Codeappend. c, append. cc, [Submit] [Status] [Web Board]
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#include<iostream>#include<cstdio>using namespace std;int cccc(int a,int b){ if(!b) return a; return cccc(b,a%b);}class Fract{public: int n,m; Fract(int a,int b):n(a),m(b) { int Max,Min,c,x,y; if(a<0) a*=-1; if(b<0) b*=-1; c=cccc(max(a,b),min(a,b)); if(m<0) { n*=-1; m*=-1; } if(c!=1) { n/=c; m/=c; } } void show() { if(n==0||m==1) cout<<n<<endl; else { cout<<n<<"/"<<m<<endl; } } operator double() { return (double)n/m; }};int main(){ int n, m; while(cin >> n >> m) { Fract fr(n, m); cout << (double)fr << " "; fr.show(); }}