1054. Averaging (20)

1054. Averaging (20)

The basic requirement of the subject is very simple: given n real numbers, calculate their average. But the complex is that some of the input data may be illegal. A "valid" input is a real number within the [ -1000,1000] interval and is up to 2 digits after the decimal point. When you calculate the average, you can't count the illegal data.

Input format:

Enter the first line to give the positive integer n (<=100). The next line gives n positive integers, separated by a space between the numbers.

Output format:

For each illegal input, output "error:x is not a legal number" in a row, where X is the input. Finally, the result is output in a row: "The average of K numbers is Y", where K is the number of legal inputs, Y is their average value, accurate to 2 digits after the decimal point. If the average cannot be calculated, replace Y with "Undefined". If k is 1, then output "The average of 1 number is Y".

Input Sample 1:

75-3.2 AAA 9999 2.3.4 7.123 2.35

Output Example 1:

ERROR:AAA is not a legal numbererror:9999 are not a legal numbererror:2.3.4 are not a legal numbererror:7.123 are not a l Egal numberthe average of 3 numbers is 1.38

Input Sample 2:

2aaa-9999

Output Example 2:

ERROR:AAA is not a legal numbererror: -9999 are not a legal numberthe average of 0 numbers are Undefined

1#include <iostream>2#include <cstdlib>3#include <cstdio>4#include <cstring>5 using namespacestd;6 intMain () {7     Char*num[ the];8     intN,count=0;9     DoubleAverage=0;TenCin>>N; One      for(intI=0; i<n;i++){ A         BOOLIsnumber=true;//Judging whether it is a legal number -         intPoint=0;//Monitor the number of decimal points -         intpoint_=0;//Monitor the number of digits after the decimal point theNum[i] = (Char*)malloc(Ten*sizeof(Char));//Application Space -Cin>>Num[i]; -         intlen=strlen (Num[i]); -         DoubleTemp=atof (Num[i]);//Convert a string to a number, use your own Baidu +         if(temp<- +|| Temp> +) isnumber=false; -          for(intj=0; j<len;j++) {//determine the individual characters of each element +             if(point==1) point_++;  A             if(num[i][j]=='-'&&j!=0){//if it contains-, then-only one and in the first position atIsnumber=false; -                  Break; -             } -             if(num[i][j]!='.'){      -                 if((num[i][j]<'0'|| Num[i][j]>'9') && (num[i][j]!='-')){ -Isnumber=false; in                      Break; -                 }        to}Else{//if it's a decimal point +point++; -             } the             if(point_>2|| Point>1){//If the decimal point is greater than one or the number of decimals is extra 2 *Isnumber=false; $                  Break;Panax Notoginseng             } -         } the         if(!isnumber) +cout<<"ERROR:"<<num[i]<<"is not a legal number"<<Endl; A         Else { thecount++; +average+=temp; -         } $     } $     if(count==1) -printf"The average of 1 number is%.2LF", average); -     Else if(count==0) theprintf"The average of 0 numbers is Undefined"); -     ElseWuyiprintf"The average of%d numbers is%.2LF", count,average/count); the     return 0; -}

1054. Averaging (20)