C + + operator overloading simple practice writing an integer wrapper class

Operator.cpp: Defines the entry point of the console application. #include "stdafx.h" #include <iostream> #include <string>using namespace Std;class integer{public:// Explicit if you add explicit, you cannot implicitly construct//implicitly construct does not cause the copy constructor call integer (int num): m_num (num) {}//Overwrite the copy constructor must value the member of the Copy object    A deep copy is also required, such as reallocating memory Integer (const integer&integer) {m_num=integer.m_num; cout<< "CPY construction FUNCTION called" &LT;&LT;ENDL;} Suffix Form//If the suffix form so-shaped participant is 0void operator++ (int i) {this->m_num=m_num+1;} Prefix form void operator++ () {this->m_num++;} Front--void operator--() {this->m_num--;} suffix form void operator--(int i) {this->m_num=m_num-1;} Overload + If you accept not Integer&integerref then the copy constructor will still trigger the integer operator+ (integer &integerref) {return integer (m_num+ Integerref.m_num);} Integer operator+ (int i) {return m_num+i;} Integer operator-(int i) {return m_num-i;} Overload =void operator= (int i) {m_num=i;} Overload + =-=void operator+= (int i) {m_num+=i;} void operator-= (int i) {m_num-=i;} return value int Toval () {return m_num;} function return assignment causes the copy construct to call the integer GeTobj () {return *this;}        Convert to a string, Const. String ToString () {char buf[10]= ""; _itoa_s (m_num,buf,10); return string (BUF);} Copy myself//only triggers a copy construct or creates an object inside the function body and takes the object as a return value to trigger the copy constructor call//If return Integer (M_num) only when a new object is returned or when a new object is created by another object initialization; is the//functor that does not trigger the copy construct integer operator () () {return *this;} Overload standard input standard output standard error output for iOS streaming class library So we can only declare << >> insert extract operator as friend function friend istream& operator >> (istream& is,integer&intobj); Friend ostream& operator << (ostream&os,integer&intobj);//Extract data from object to variable < < >> operator overload void operator>> (int &i) {i=m_num;} Output to object void operator<< (int i) {m_num=i;} Private:int m_num;protected:};//Reload IO istream& operator >> (istream&is,integer&intobj) {is>> Intobj.m_num; return is;} ostream& operator << (ostream&os,integer&intobj) {os<<intobj.m_num; return OS;} int _tmain (int argc, _tchar* argv[]) {//implicitinteger Integerobj1=1;integer Integerobj2=2;//integerobj1=integerObj2; The copy constructor is not triggered by Integer obj=integerobj1 to trigger the copy construction call//equivalent to integerobj++0integerobj1++;//equivalent to ++x++integerobj1; cout<< "integerobj1=" <<integerobj1.toval () <<endl;integer intobjcmb=integerobj1+integerobj2; cout<< "intobjcmb=" <<intobjcmb.toval () <<endl;integer w=integerobj1;cout<< "w=" <<w. ToString () <<endl;w+=2;cout<< "w+2=" <<w.tostring () <<endl;cout<< "Copy w=" <<w () . ToString () <<endl;//overloads the standard input and output .....w=125;cout<< "w=" <<w<<endl;int i;w>>i;cout< < "i=w=" <<w<<endl;w<<1000;cout<< "w=" &LT;&LT;W&LT;&LT;ENDL; w>>i;cout<< "i= W= "&LT;&LT;W&LT;&LT;ENDL; return 0;}

C + + operator overloading simple practice writing an integer wrapper class