Php computing time interval implementation program code

In the article, I have talked a lot about the implementation principles of the program code for implementing the php computing time interval and how to analyze how to do this function. if you need it, you can take a closer look. The following example shows how many seconds ago I posted a post on the forum and analyzed the actual situation...

In the article, I have talked a lot about the implementation principles of the program code for implementing the php computing time interval and how to analyze how to do this function. if you need it, you can take a closer look.

The following example shows how many seconds ago we posted a post on the forum and other functions,

Analysis

Actual time PHP

1 second, 2 "seconds"

______________________

30 seconds = 60

5 minutes = 60*10 // here I think it should be five minutes, not one minute. in my opinion, the minute should be 60*2.

10 minutes = 60*20

30 minutes = 60*60

1 hour = 60*60*2

2.5 hours = 60*60*5

Principle

Use the current time (), minus the new time when you input the information (note that it is a timestamp), and the difference is the number of seconds, which can be converted according to your own needs. For example, if you want to convert it to minutes, divide it by 60.

Instance

The code is as follows:

/** * Time difference calculation * * @ Param Timestamp $ time * @ Return String Time Elapsed * @ Author Shelley Shyan * @ Copyright http://www.phprm.com (Professional PHP Architecture) */ Function time2Units ($ time) { $ Year = floor ($ time/60/60/24/365 ); $ Time-= $ year * 60x60*24*365; $ Month = floor ($ time/60/60/24/30 ); $ Time-= $ month * 60*60*24*30; $ Week = floor ($ time/60/60/24/7 ); $ Time-= $ week * 60*60*24*7; $ Day = floor ($ time/60/60/24 ); $ Time-= $ day * 60*60*24; $ Hour = floor ($ time/60/60 ); $ Time-= $ hour * 60*60; $ Minute = floor ($ time/60 ); $ Time-= $ minute * 60; $ Second = $ time; $ Elapse = ''; $ UnitArr = array ('year' => 'year', 'month' => 'month', 'week' => 'week ', 'Day' => 'day ', 'Hour '=> 'hour', 'mine' => 'Minute ', 'second' => 'second' ); Foreach ($ unitArr as $ cn => $ u) { If ($ u> 0) { $ Elapse =$ u. $ cn; Break; } } Return $ elapse; } $ Past = 2052345678; // Some timestamp in the past $ Now = time (); // Current timestamp $ Diff = $ now-$ past; Echo 'posted in'. time2Units ($ diff '; ?>

This is written by a beginner.

The code is as follows:

$ Regist1 = "05/12/2006 "; $ Regist2 = "10/05/2007 "; List ($ month1, $ day1, $ year1) = explode ("/", $ regist1 ); List ($ mon2,$ day2, $ year2) = explode ("/", $ regist2 ); $ Regist1 = mktime (0, 0, $ month1, $ day1, $ year1 ); $ Regist2 = mktime (0, 0, $ mon2, $ day2, $ year2 ); $ Time_difference = $ regist2-$ regist1; Echo ("Time difference :"); Echo date ("Y", $ time_difference)-1970; Echo ("year "); Echo date ("m", $ time_difference)-1; Echo ("months "); Echo date ("d", $ time_difference)-1; Echo ("day "); ?>

If you like it, choose it.

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