Functions in Python receive extra parameters

Code:

def Fun (x):     return x     Print Fun (10)

The function fun (x) accepts the argument is x, passing in the number "10", the return value of the print function is 10, if I pass multiple parameters, the program will go wrong, such as:

def Fun (x):     return x Print (Fun (10,20))

Traceback (most recent):   " aa.py "  in <module>    print(10,201 argument (2 given)

The result is: 2 parameters are given. To solve this problem, introduce *args to put the extra parameters into the tuple, such as:

def Fun (x, *args):    print  args    return  x     Print(Fun (10,20))

In this case, X only accepts the first parameter, and the others are stored in the args tuple, as a result:

(10,)

Tuple is not stored in the dictionary type of data, if I store the dictionary type data will be error? See:

def Fun (x, *args):    print  args    return  x      Print(Fun (10,20,y=2))

Traceback (most recent):   " aa.py "  in <module>    print(10,20,y=2'y'

At this point, give an error: Catch an unknown keyword parameter y, in order to solve this we need to introduce **kw to solve the incoming parameter is the dictionary type of data, see:

def Fun (x, *args, * *kw)    :print  kw    print  args     return x     Print (Fun (10,20,y=2))

Running results such as:

{'y': 10}

Look at the whole effect:

def Fun (x, *args, * *kw)    :print  kw    print  args      return  x    print(Fun (10,20,40,50.5,y=2,z=3,f=5.5))

Operation Result:

{'y'z'f': 5.5} (+, 50.5)10

The main note is: Fun (x, *args, **kw) when the function is called, the incoming dictionary parameter is not allowed to pass in x = * This type, there will be an error, such as:

Traceback (most recent):   " aa.py "  in <module>    print(10,20,40,50.5,z=3,x=2,y=5.5for'  x'

  " aa.py ", line 9    print(x=2,10,20,40,50.5,z=3,y=5.5)) Syntaxerror:non-keyword Arg after Keyword arg

Functions in Python receive extra parameters