Golang Base--strcut Structural body

Source: Internet
Author: User
  • struct structs are similar to class classes in the Python language, and the elements of a struct class can be a variable, or a function or other type, like the properties and methods of a python.

    // struct结构体,类似python语言中的class类package mainimport "fmt"type person struct { //定义一个strcut    Name string    Age  int}func main() {    a := person{}    //赋值给一个变量a    fmt.Println(a)    a.Name = "faily"  //为结构体赋值    a.Age = 28    fmt.Println(a)}/*输出结果    { 0}            //空结构体时,int元素为0{faily 28}*/
  • Simple way to initialize a struct

    package mainimport "fmt"type person struct { //定义一个strcut    Name string    Age  int}func main() {    a := person{ //也可以这样初始化一个结构体        Name: "msy",        Age:  27,    }    fmt.Println(a)}
  • The
  • Struct is also a value type , which means that when passed, the copy is a value, the normal path cannot change the value within the structure, and it needs to be modified by pointer

     package Mainimport ' fmt ' type person struct {//define a strcut Name string age Int}func main () {a: = person{/ /Initialize struct Name: "MSY", Age:27,} fmt. Println ("1", a) A (a) fmt. Println ("3", a) B (&a)//pointer refers to FMT. Println ("4", a)}func a (per person) {///parameter references person--struct per. Age = 13//Initializes the value of the person property to FMT. Println ("2", per)}func B (per *person) {//pass pointer per. Age =13 FMT. Println ("2", per)}/* output initialization: 1 {MSY 27} Modification of A:2 {MSY 13} modification failed: 3 ' {MSY 27} modified B:2 {MSY 13} modified successfully: 3 "{MSY 13 } */
  • It is more convenient to modify the structure by using the structure pointer when it is recommended to initialize the struct body.

    package mainimport "fmt"type person struct { //定义一个strcut    Name string    Age  int}func main() {    a := &person{ //初始化结构体,建议使用结构的指针        Name: "msy",        Age:  27,    }    a.Name = "MYF" //这种方式就可以直接修改结构体    fmt.Println("1", a)    A(a) //此时就可以直接修改结构体    B(a)    fmt.Println("3", a)}func A(per *person) {           //传递指针    per.Age = 13                //初始化person属性的值    fmt.Println("2", per)}func B(per *person) { //传递指针    per.Age = 100    fmt.Println("2", per)}/*输出1 &{MYF 27}2 &{MYF 13}2 &{MYF 100}3 &{MYF 100}*/
  • Anonymous structure: Structure without a name

    package mainimport "fmt"func main() {    a := &struct {      //指向结构体指针        Name string        Age  int    }{                  //直接初始化        Name: "moshaoying",        Age:  27,    }       fmt。Println(a)}/*输出&{moshaoying 27}*/
  • Nested anonymous struct, initialization mode

      package Mainimport "FMT" type person struct {//nested anonymous struct Name string A GE int Content struct {Phone int Addr string}}func main () {A: = Person{name: "Moshaoying", age:22} A.content.phone = 13636269334//nested anonymous struct initialization mode a.content.addr = "Shanxi,xian" FMT. Println (a)}/* output {moshaoying {13636269334 shanxi,xian}}*/ 
  • Struct-body comparison: Naming is part of a struct, so you can compare it only if the struct is named the

      package Mainimport "FMT" type person struct {/ /nested anonymous struct name string age int}type person1 struct {Name string Age Int}func main () {A: = Person{name: "Mo Shaoying ", age:22} B: = Person1{name:" Moshaoying ", age:22} c: = Person{name:" Moshaoying ", age:22} D: = per Son{name: "Moshaoying", age:21} fmt. Println (A = = b) fmt. Println (A = = c) fmt. Println (A = = d)}/* output error a=b Invalid operation:a = B (mismatched types person and Person1) a=c Truea=d false*/
          
  • The
  • Struct does not inherit from the Python class, but the struct also has a similar function, nested within the struct, to inherit the properties of the other struct

      package Mainimport "FMT" type Human struct {Sex int}type person struct {//struct inherits (nested) human Name string Age Int}func main () {A: = Perso N{name: "Failymao", Age:22, human:human{sex:250}}//The first way, note the principle of FMT. Println (a)//second Way a.name = "Allen" a.age = A.sex = 222 FMT. Println (a)}/* output error First way: {{22} Failymao} The second way: {{222} Allen 29}*/ 
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