Hangzhou Electric 2027--Statistical vowel

Source: Internet
Author: User

Statistical vowels

Time limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others)
Total submission (s): 46701 Accepted Submission (s): 19038


Problem description counts the number of occurrences of each vowel in a string.

Input data first consists of an integer n, which represents the number of test instances, followed by a string of n lines with a length of not more than 100.

Output outputs 5 rows for each test instance, in the following format:
A:num1
E:num2
I:num3
O:num4
U:num5
Multiple test instances are separated by a blank line.

Please pay special attention: There is no blank line after the last output:)

Sample Input2 Aeiou My name is Ignatius

Sample outputa:1 e:1 i:1 o:1 u:1 a:2 e:1 i:3 o:0 u:1

Authorlcy

SOURCEC Language programming Exercises (iv)

Recommendlcy | We have carefully selected several similar problems for you:1062 1256 1020 1075 2072
1#include <stdio.h>2#include <string.h>3 intMain ()4 {5     Charstr[ the] ;6     inti, N;7      while(~SCANF ("%d", &N))8     {9GetChar ();//Why do you have to put it here? Ten           while(n--) One         { A gets (str); -             intLen =strlen (str); -             intA=0, b=0, c=0, d=0, e=0 ; the              for(i=0; i<len; i++) -             { -                 if(Str[i] = ='a') -a++ ; +                 if(Str[i] = ='e') -b++ ; +                 if(Str[i] = ='I') AC++ ; at                 if(Str[i] = ='o') -d++ ; -                 if(Str[i] = ='u') -e++ ; -             } -printf"a:%d\n", a); inprintf"e:%d\n", b); -printf"i:%d\n", c); toprintf"o:%d\n", d); +printf"u:%d\n", e); -             if(n!=0) theprintf"\ n") ; *         } $     }Panax Notoginseng     return 0 ; -}

Hangzhou Electric 2027--Statistical vowel

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