Huawei Computer Testing Questions (convert digital string to binary-java), Huawei-java
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/** Question: convert a numeric string to a binary string
* Description: enter a string of Integers to convert each integer to a binary number. If the last and third bits are "0", the output value is "0". If the last and third bits are "1 ", output "1 ".
Question category: bitwise operation
Difficulty: elementary
Score: 60
Run Time Limit: 10 Sec
Memory limit: 128 MByte
Phase: apply for an exam
Input: a string of integers with a length less than 1024. The integers are separated by spaces.
Output: an integer string of 1/0 separated by Spaces
Sample input: 240 0
Sample output: 0 0
Answer:
*/
1 import java.util.Scanner; 2 3 public class Main { 4 5 public static void main(String[] args) { 6 7 String bitStr = ""; 8 9 Scanner cin = new Scanner(System.in);10 String str = cin.nextLine();11 12 bitStr = getBitString(str);13 14 System.out.println(bitStr);15 cin.close();16 17 }18 19 private static String getBitString(String str) {20 21 int len = 0;22 int bit = 0;23 int num = 0;24 StringBuilder sb = new StringBuilder();25 26 String[] strArray = str.split(" ");27 len = strArray.length;28 29 if(len >= 1024)30 {31 return "";32 }33 34 for(int i = 0; i < len; i++)35 {36 num = Integer.parseInt(strArray[i]);37 num /= 4;38 bit = num % 2;39 40 sb.append(bit+" ");41 }42 43 return sb.toString().substring(0, sb.length()-1);44 }45 46 }
How to convert a string to a binary number in java
Java. lang. Integer: the API package contains the hexadecimal conversion function.
Public static String toBinaryString (int I)
Public static String toHexString (int I)
Public static String toOctalString (int I)
All three functions can convert decimal integers into two, one, six, and eight decimal integers.
However, the converted result is in the string format.
How to convert a binary number into a corresponding string in java
Public static String getSecret (byte [] B) {// obtain the ciphertext
String string = "";
Int c = B. length/6;
Int last = B. length % 6;
Int point = 0;
Int temp = 0;
For (int I = 0; I <c; I ++ ){
For (int j = 6; j> 0; j --){
Int temp1 = Integer. valueOf (B [point])-48;
Int z = 0;
While (z <J-1 ){
Temp1 = temp1 * 2;
Z ++;
}
Point ++;
Temp = temp + temp1;
}
String string2 = String. valueOf (char) temp );
String = string + string2;
Temp = 0;
}
For (; last> 0; last --){
Int z = 0;
Int temp1 = Integer. valueOf (B [point])-48;
While (z <last-1 ){
Temp1 = temp1 * 2;
Z ++;
}
Point ++;
Temp = temp + temp1;
}
String string2 = String. valueOf (char) temp );
String = string + string2;
Return string;
}