Huawei machine Test--speed

Source:

Describe:	A car with a fixed speed, the driver sees a reading on the odometer (6-digit odometer) at 10 o'clock in the morning is a symmetric number (that is, the number reads from left-to-right and right-to-left reading is exactly the same, for example, 95859 km). A new symmetry number appeared on the odometer two hours later. Q. What is the speed (km/h) of the car? Interface description Prototype: int calcspeedofcar (int icurrentmileage, int * picarspeed); Input parameters: int pccurrentmileage: Current number of miles (for symmetric number) (Pccurrentmileage ≤ 999999) Output parameters: int * picarspeed: car Speed return value: 0: Car speed calculation success 1: Car speed calculation fails, the next symmetric number cannot be found within the range of the odometer
Knowledge point:	Engineering environment use vs2005  
Software training camp
Practice Stage:	Primary

The topic is simple, pay attention to a few key points, odd digits or even digits, whether the integer is full 9, whether the middle symmetry position is 9, and this symmetric number is required to be an integer less than seven digits, to do boundary detection ~

#include <iostream>using namespace std; /* Function: Calculates speed prototype based on mileage: int calcspeedofcar (int icurrentmileage, int * picarspeed), input parameter: int pccurrentmileage: Current mileage (for symmetric number) (p ccurrentmileage≤999999) return value: Car speed (km/h) */int calcspeedofcar (int icurrentmileage, int * picarspeed) {/* Implement function here */cha R Tmp[7],tmp2[8];itoa (icurrentmileage,tmp,10), int i,slen=strlen (TMP), if (slen>6) return 1;if (slen%2)//Odd {if (tmp[ slen/2]< ' 9 ') {tmp[slen/2]++;*picarspeed= (atoi (TMP)-icurrentmileage)/2;return 0;} else//tmp[slen/2]== ' 9 ' {itoa (icurrentmileage+1,tmp2,10); if (strlen (TMP2) >slen) {if (slen>5) return 1;* Picarspeed=1;return 0;} I=slen/2;while (tmp[i]== ' 9 ') {tmp[i]= ' 0 '; i--;} Tmp[i]++;for (i=0;i<slen/2;i++) tmp[slen-i-1]=tmp[i];*picarspeed= (atoi (TMP)-icurrentmileage)/2;return 0;}} else//even {itoa (icurrentmileage+1,tmp2,10), if (strlen (TMP2) >slen) {if (slen>5) return 1;*picarspeed=1;return 0;} I=slen/2-1;while (tmp[i]== ' 9 ') {tmp[i]= ' 0 '; i--;} Tmp[i]++;for (i=0;i<slen/2;i++) tmp[slen-1-i]=tmp[i];*picarspeed= (atoi (TMP)-icurrentmileage)/2;return 0;} return 0;} int main () {int speed; Calcspeedofcar (1991,&speed); Cout<<speed<<endl;return 0;}

Huawei machine Test--speed