I can't help but remind me that I have read some tutorials about mysql injection and wrote the injection vulnerability into mysql, you need to add the # number to comment out the statements that may be followed by errors. Do you not know that writing the # number in the address bar does not work? Do you have to write it as % 23? If the owner points to fail, test OK? Don't take it bad
I can't help but remind me that I have read some tutorials about mysql injection and wrote the injection vulnerability into mysql, you need to add the # number to comment out the statements that may be followed by errors. Do you not know that writing the # number in the address bar does not work? Do you have to write it as % 23? If the owner points to fail, test OK? Don't take it bad
I can't help but remind you about the problem of # comments for mysql injection.
Recently I accidentally read several tutorials about mysql injection. When writing to the injection vulnerability, I need to add the # number to comment out the statements that may cause errors,
Don't you know that writing # in the address bar doesn't work. You have to write it as % 23 to get it?
If the owner points to fail, test OK? Don't take others bad?