I Love You Too HDU 2816, hdu2816

I Love You Too HDU 2816, hdu2816

Description

This is a true story. A man showed his love to a girl, but the girl didn't replied clearly, just gave him a Morse Code:
****-/*----/----*/****-/****-/*----/---**/*----/****-/ *----/-****/***--/****-/*----/----*/**---/-****/**---/ **---/***--/--***/****-/He was so anxious that he asked for help in the Internet and after one day a girl named "Pianyi angel" found the secret of this code. She translate this code as this five steps:
1. First translate the morse code to a number string: 4194418141634192622374
2. Second she cut two number as one group 41 94 41 81 41 63 41 92 62 23 74, According to standard Mobile phone can get this alphabet: GZGTGOGXNCS

3. Third she change this alphabet according to the keyboard: QWERTYUIOPASDFGHJKLZXCVBNM = ABCDEFGHIJKLMNOPQRSTUVWXYZ
So, we can get OTOEOIOUYVL
4. Fourth, divide this alphabet to two parts: OTOEOIAnd OUYVL, Compose again. we will get OOTUOYEVOLI
5. Finally, reverse this alphabet the answer will appear: I LOVE YOU TOO

I guess you might worship Pianyi angel as me, so let's Orz her.
Now, the task is translate the number strings.

Input

A number string each line (length <= 1000). I ensure all input are legal.

Output

An upper alphabet string.

Sample Input

419441814163419262237441944181416341926223

Sample Output

ILOVEYOUTOOVOYEUOOTIO

#include<iostream>#include<cstdio>#include<cstring>#include<algorithm>#include<cmath>#include<queue>using namespace std;int main(){    char ss[1314],s[1314];    char* a[]={"ABC","DEF","GHI","JKL","MNO","PQRS","TUV","WXYZ"};    char b[]="KXVMCNOPHQRSZYIJADLEGWBUFT";    char d[]="QWERTYUIOPASDFGHJKLZXCVBNM";    //for(int i=0;i<26;i++)    //    cout<<b[d[i]-'A']<<" ";    while(gets(ss))    {        int m=strlen(ss);        int len=0;        for(int i=0;i<m;i++)            if(ss[i]!=' ')                s[len++]=ss[i];        char s0[520];        int x=0;        for(int i=0;i<len;i+=2)        {            s0[x++]=b[a[s[i]-'2'][s[i+1]-'1']-'A'];                    }        char s1[520];        int y=0;        for(int i=0;i<x;i+=2)        {            s1[i]=s0[y++];            }        for(int i=1;i<x;i+=2)        {            s1[i]=s0[y++];        }        for(int i=y-1;i>=0;i--)        {            putchar(s1[i]);        }        printf("\n");    }}