Implement file upload in Windows Forms Program

Source: Internet
Author: User

Sometimes we may use Windows FormsProgramUpload a file. The following is a simple example. The button click event is as follows:

Openfiledialog dialog = new openfiledialog ();

If (dialog. showdialog () = dialogresult. OK)

{

VB. devices. Network NETWORK = new Microsoft. VisualBasic. devices. Network ();

Try

{

String filename = dialog. filename;

String parameter filename = system. Io. Path. getfilename (filename );

Network. uploadfile (filename, txtserverpath. Text + @ "\" + invalid filename, txtusername. Text, txtpassword. Text );

MessageBox. Show ("uploaded ");

}

Catch (exception ex)

{

MessageBox. Show (ex. Message );

}

}

Add a reference to the Microsoft. VisualBasic assembly and import the namespace

Using VB = Microsoft. VisualBasic

 

Put several controls on the form, as shown in

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