Implementation of A. NET generic JSON parsing/construction class

In. NET Framework 3.5 provides a JSON Object serialization tool, but it is strongly typed. You must first define a type according to the JSON object format and add the type to the JSON serialization feature. This article will try to provide a highly flexible JSON generic type (JsonObject) for JSON parsing and serialization.

Assume that the content of the JSON object is as follows:

1. {

2.     orders: {

3.         date: 21:31:59,

4.         name: Xfrog,

5.         books: [{

6. Name: C # core network programming,

7.             publish: 2010-3-24

8.         }, {

9. Name: C # entry-level Classic Chinese edition,

10.             publish: 2009-10-16

11.         }]

12.     },

13.     blog: http://www.cnblogs.com/xfrog

14. }

 

You can use the following methods to build a JsonObject:
Method 1:

1. // Use the standard Constructor

2. JsonObject json = new JsonObject();

3. json["orders"] = new JsonProperty(new JsonObject());

4. json["blog"] = new JsonProperty("http://www.cnblogs.com/xfrog");

6. JsonObject config = json.Properties<JsonObject>("orders");

7. json["orders"]["date"] = new JsonProperty(DateTime.Now.ToLongTimeString());

8. json["orders"]["name"] = new JsonProperty("Xfrog");

9. json["orders"]["books"] = new JsonProperty();

11. JsonProperty book = json["orders"]["books"].Add(new JsonObject());

12. Book ["name"] = new JsonProperty ("C # core network programming ");

13. book["publish"] = new JsonProperty("2010-3-24");

15. book = json["orders"]["books"].Add(new JsonObject());

16. Book ["name"] = new JsonProperty ("C # ");

17. book["publish"] = new JsonProperty("2009-10-16");

 

Method 2: