In Java why print char array output is value, while others are address value __java base

First, the processing of the array of println methods is first converted to string type, we can enter the println source code look, I was creating a string array to look at the next

    public void println (Object x) {
        String s = string.valueof (x);
        Synchronized (this) {
            print (s);
            NewLine ();
        }
    

First he turns into a string and then goes into the Print method

    public void print (String s) {
        if (s = = null) {
            s = ' null ';
        }
        Write (s);
    }

Next, we'll go into the write method.

    private void Write (String s) {
        try {
            synchronized (this) {
                ensureopen ();//confirm that the output stream is open
                textout.write (s) ;//is a bufferwriter, write to the buffer
                textout.flushbuffer ();//Refresh Buffer
                charout.flushbuffer ();//outputstreamwriter
                if (AutoFlush && (s.indexof (' \ n ') >= 0))
                    Out.flush ()//Here is the one with the char array, and he flushes the string s to the output stream of the console. But remember he didn't have to ToString Method-
            associated
        }
        catch (Interruptedioexception x) {
            thread.currentthread (). Interrupt ( );
        }
        catch (IOException x) {
            trouble = true;
        }
    }

So let's look at the write method for the char array.

    private void Write (char buf[]) {
        try {
            synchronized (this) {
                ensureopen ();
                Textout.write (BUF);
                Textout.flushbuffer ();
                Charout.flushbuffer ();
                if (AutoFlush) {//We can see that he is writing each character to the output stream of the console. for
                    (int i = 0; i < buf.length i++)
                        if (buf[i] = = ' \ n ')
                            Out.flush ()
                ;
        }}} catch (Interruptedioexception x) {
            thread.currentthread (). interrupt ();
        }
        catch (IOException x) {
            trouble = true;
        }
    }

In fact, this is the second time encountered this problem, but not very clear before, this lane clearly recorded, but also for everyone to refer to